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tresset_1 [31]
4 years ago
8

What is the difference between an Isotope and an Allotrope?

Chemistry
1 answer:
Kaylis [27]4 years ago
8 0
Allotropes are elements on the periodic table that have more than one crystalline form . There are three forms of the element carbon : Diamond, Graphite, and Fullerenes. Isotopes are atoms of the same element with the same atomic number but have a different mass number.
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Please help guys if you know it!
iogann1982 [59]
The second one is correct
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3 years ago
Steam is a form of _____.
kramer

The answer to this question is A. Humidity.. because humitity causes steam

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Why does the boiling point of water change at high elevation (maybe in Denver, Colorado, the Mile-High City) compared to sea lev
Oksanka [162]

Explanation:

This is due to a reduction in atmospheric pressure – pressure due to the weight of the overlying air column). Remember that the higher the altitude the lower the air density and subsequently the lower the air pressure.

Therefore when heating water at higher altitude the vapor pressure of the water at the surface overpowers the atmospheric pressure – which is slightly lower than at sea level – even before the water temperatures reach 100 degrees centigrade.

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3 years ago
A student wants to test if giving dogs a toy to play with makes their tail wag more. He gives dog toys to one group, while anoth
kicyunya [14]

Answer:

Experimental: the dogs who get the toys

Control: the dogs who dont recieve a toy

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4 0
3 years ago
A 100.0-g sample of water at 27.0oC is poured into a 71.0-g sample of water at 89.0oC. What will be the final temperature of the
Sedbober [7]

<u>Answer:</u> The final temperature will be 52.74^oC

<u>Explanation:</u>

Calculating the heat released or absorbed for the process:

q=m\times C\times (T_2-T_1)

In a system, the total amount of heat released is equal to the total amount of heat absorbed.

q_1=-q_2

OR

m_1\times C\times (T_f-T_1)=-m_2\times C\times (T_f-T_2) ......(1)

where,

C = heat capacity of water = 4.184J/g^oC

m_1 = mass of water of sample 1 = 100.0 g

m_2 = mass of water of sample 2 = 71.0 g

T_f = final temperature of the system = ?

T_1 = initial temperature of water of sample 1 = 27^oC

T_2 = initial temperature of the water of sample 2 = 89.0^oC

Putting values in equation 1, we get:

100.0\times 4.184\times (T_f-27)=-71.0\times 4.184\times (T_f-89)\\\\171T_f=9019\\\\T_f=\frac{9019}{171}=52.74^oC

Hence, the final temperature will be 52.74^oC

6 0
3 years ago
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