Answer:
Actually, The Henderson - Hasselbalch equation allows you to calculate the pH of the buffer by using the pKa of the weak acid and the ratio that exists between the concentrations of the weak cid and conjugate base. The pKa of formic acid is equal to 3.75. In this case, the pH of the solution will be equal to the acid's pKa .
The reaction is of order three with respect to the reactant.
<h3>Explanation</h3>
The rate of a reaction of order n about a certain reactant is proportion to the concentration of that reactant raised to the n-th power. This is true only if concentrations of any other reactants stay constant in the whole process.
In other words, Rate = constant × [Reactant]ⁿ, Rate ∝ [Reactant]ⁿ. (The symbol "∝" reads "proportional to".)
In this question,
[4 × Reactant]ⁿ ÷ [Reactant]ⁿ = 64.
In other words, 4ⁿ = 64, where n is the order of the reaction with respect to this reactant.
It might take some guesswork to find the value of n. Alternatively, n can be solved directly with a calculator using logarithms. Taking natural log of both sides:
.
Evaluating
on Google or on a calculator with support for ln (the natural log) will give the value of n- no guesswork required.
n = 3. Therefore, the reaction is of order three with respect to this reactant.
Answer:
C. the relative molecular mass of the compound
Explanation:
Like molecular formulas, empirical formulas are not unique and can describe a number of different chemical structures or isomers. <u>To determine an empirical formula, the relative molecular mass of the composition of its elements</u> can be used to mathematically determine their ratio.
Answer:
25.6mL NaOH
Explanation:
We are given the Molarity of the solution (
) and the volume of the solution (.02L).
By multiplying the two together, we can find the moles of solution that are reacted with HCl.

This gives us .0082 moles of HCl.
We then find the moles of NaOH that are needed to react with the HCl using the equation.

As HCl and NaCl have a 1:1 ratio, we need .0082 mol of NaOH.
Dividing this value by the Molarity of the solution

Gives us the answer, in Liters (.0256), which we can then divide by 100 convert to mL.