Work=f.d
Work=100*50 = 500
Power = work/time = 500/4
=125 watt
Without options I can simply compare a scientific investigation to a demonstration:
<span>An investigation is a process when you are answering a question about the answer of which you do not know while a demonstration is a display or show of how something happens, when you already know the outcome.
</span>
Answer:
<h2>
2.5 m</h2>
Explanation:
Load ( L ) = 500 N
Effort ( E ) = 200 N
Load distance ( LD ) = 3 m
Effort distance ( ED ) = ?
Now, Let's find the Effort distance ( ED )
We know that,
Output work = Input work
i.e L × LD = E × ED
plug the values
multiply the numbers
Swipe the sides of the equation
Divide both sides of the equation by 200
Calculate
Hope this helps..
best regards!!
Answer:
1.08 m/s^2
Explanation:
The maximum value of static friction F_s = μ_s mg
where μ_s = coefficient of static friction
m= mass of box= 50kg
g= 9.81 m/s^2 , acceleration due to gravity
F_s = 0.5×50×9.81 =245 N
Since, the applied force is greater than the maximum value of static friction F_s, the object must be in motion. Hence, kinetic friction must be taken into account and not static friction.
By equilibrium condition
ma = F - μ_k m g
where F = 250 N, μ_k = coefficient of kinetic friction = 0.4, m= 50 Kg
a = acceleration of the box
50a = 250-0.4×50×9.81
Solving we get a= 1.08 m/s^2
