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Svetach [21]
4 years ago
7

Process of changing a liquid into a gas

Physics
2 answers:
Komok [63]4 years ago
7 0
The process of changing a liquid to a gas is called evaporation. 
lions [1.4K]4 years ago
3 0
The process is called evaporation. Liquid turns into gas. 
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If your car tachometer says your engine is moving at 1200 RPM, then what is it's angular velocity in Rad/sec?
Ostrovityanka [42]

Answer:

125.66 R/s

Explanation:

First    1200  r / min = 20 r/sec

20 r/s  *  2pi Radians / r = 40 pi Radians / sec = 125.66 R/s

3 0
2 years ago
toy car A drives with a steady force of 35N and covers 2000 m with fully charged battery. toy car B drives with a steady force o
marissa [1.9K]

Answer:

toy car drives with study force of 35 Newton and covers 2000 with fully charged battery toy car b drives with a study for 80 Newton how far will it be able to drive using the same fully charged battery as karya

8 0
3 years ago
If you push on a wall of a building what will happen
mixas84 [53]

Answer: It will push back with an equal amount of force.

8 0
3 years ago
Una carga positiva de 4 x 10-5 C, se encuentra a 0.05 m de otra carga positiva de 2 x 10-5 C. Calcular la fuerza que se ejerce e
KATRIN_1 [288]

Answer:

La fuerza que se ejerce entre las dos cargas es 2880 N.

Explanation:

La ley de Coulomb indica que los cuerpos cargados sufren una fuerza atractiva o repulsiva al acercarse. La fuerza es atractiva si las cargas son del signo opuesto y repulsión si son del mismo signo. El valor de la fuerza es proporcional al producto del valor de sus cargas e inversamente proporcional al cuadrado de la distancia que los separa. Esto se expresa matemáticamente como:

F=k*\frac{Q*q}{r^{2} }

donde:

  • F es la fuerza eléctrica de atracción o repulsión. Se mide en Newtons (N).
  • Q y q son los valores de las dos cargas puntuales. Se miden en culombios (C).
  • r es el valor de la distancia que los separa. Se mide en metros (m).
  • k es una constante de proporcionalidad llamada constante de la ley de Coulomb.

En este caso:

  • F= ?
  • Q= 4*10⁻⁵ C
  • q= 2*10⁻⁵ C
  • r= 0.05 m
  • k= 9*10⁹ \frac{N*m^{2} }{C^{2} }

Reemplazando:

F=9*10^{9} \frac{N*m^{2} }{C^{2} }*\frac{4*10^{-5} C*2*10^{-5}C }{(0.05 m)^{2} }

F= 2880 N

<u><em>La fuerza que se ejerce entre las dos cargas es 2880 N.</em></u>

7 0
3 years ago
A student has a beaker containing 55g of water at 100°c. how much heat is needed to convert the water to steam
masha68 [24]
Answer is: 124135 J.
m(water) = 55g.
T(water) = 100°C.
Q = ?
Q - heat needed to convert water to steam.
∆Hvap = 2257 J/g
∆Hvap - enthalpy of vaporization is the amount of energy <span> needed to transform the liquid substance into a gas.
Q = </span>∆Hvap · m(water) = 2257 J/g · 55g = 124135 J.

5 0
3 years ago
Read 2 more answers
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