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melisa1 [442]
3 years ago
12

Compare the orderliness of the particles. In general, which state has the most orderly arrangement?

Physics
2 answers:
Archy [21]3 years ago
7 0

Answer:

The particles in solids are arranged in a more orderly manner than they are in liquids and gases.

alexandr1967 [171]3 years ago
5 0
The state of matter which has the most orderly arrangement is solid. Here is the order of the three basic states of matter arranged from fastest to slowest, it's better to memorize it :<span>gas, liquid, solid. Also, remember that the colder your solid is, the more ordered it is.</span>
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If the net torque is zero, what does this imply about the clockwise and counterclockwise torques.
lapo4ka [179]

Answer:

Explanation:

When two forces acting on a line of action and they are equal in magnitude but opposite it direction, it forms a couple.

Torque is defined as the product of either force and the perpendicular distance between the two forces.

It is a vector quantity.

The net torque is zero, it means the anticlockwise torque is equal to the clockwise torque.

It means they balances each other.

6 0
3 years ago
The gauge pressure in the tires of your car is 210 kPa (30.5 psi) when the temperature is 25°C (77 °F). Several days later it is
DaniilM [7]

Under the assumption that the tires do not change in volume, apply Gay-Lussac's law:

P/T = const.

P = pressure, T = temperature, the quotient of P/T must stay constant.

Initial P and T values:

P = 210kPa + 101.325kPa

P = 311.325kPa (add 101.325 to change gauge pressure to absolute pressure)

T = 25°C = 298.15K

Final P and T values:

P = ?, T = 0°C = 273.15K

Set the initial and final P/T values equal to each other and solve for the final P:

311.325/298.15 = P/273.15

P = 285.220kPa

Subtract 101.325kPa to find the final gauge pressure:

285.220kPa - 101.325kPa = 183.895271kPa

The final gauge pressure is 184kPa or 26.7psi.

8 0
3 years ago
A 1350 kg car travels at 12 m/s. What is it's kinetic energy
Lana71 [14]

Hello!

A 1350 kg car travels at 12 m/s. What is it's kinetic energy ?

We have the following data:  

m (mass) = 1350 kg  

v (velocity) = 12 m/s  

KE (kinetic Energy) = ? (in Joule)  

Formula to calculate kinetic energy:

\boxed{KE = \dfrac{1}{2} *m*v^2}

Solving:

KE = \dfrac{1}{2} *m*v^2

KE = \dfrac{1}{2} *1350*12^2

KE = \dfrac{1}{2} *1350*144

KE = \dfrac{194400}{2}

\boxed{\boxed{KE = 97200\:Joule}}\:or\:\boxed{\boxed{KE = 97.2\:kJ}}\Longleftarrow(kinetic\:energy)\:\:\:\:\:\:\bf\blue{\checkmark}

_______________________

\bf\green{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}

5 0
3 years ago
A projectile is shot directly away from Earth's surface. Neglect the rotation of the Earth.
Maksim231197 [3]

Answer:

Explanation:

We shall apply law of  conservation of mechanical energy for projectile being thrown .

Total energy on the surface = total energy at height h required

a ) At height h , velocity = .351 x ( 2 GM/R x h )

\frac{-GM}{R} + \frac{m\times(.351\times\sqrt{2GM})^2 }{2R } = \frac{-GMm}{R+h} + 0

\frac{-GMm}{R} +\frac{1}{2}\times  \frac{-2GMm}{R} \times0.123=\frac{-GMm}{R+h}

\frac{0.877GMm}{R} =\frac{-GMm}{R+h}

h = .14 R

b )

\frac{-GM}{R} + \frac{m\times(.351\times2GM) }{2R } = \frac{-GMm}{R+h} + 0

\frac{-0.649GMm}{R} = \frac{-GMm}{R+h}

h = .54 R

c ) least initial mechanical energy required at launch if the projectile is to escape Earth

= GMm / R + 1/2 m (2GM/R)

= 0

5 0
3 years ago
Problema 1
Ronch [10]

Answer:The line plot shows the number of cans a class of students at Parkway School collected for a canned food drive.

Part A: How many students collected cans of food?

Part B: What is the median number of cans of food collected?

Explanation:

7 0
2 years ago
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