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3 years ago

Compare the orderliness of the particles. In general, which state has the most orderly arrangement?

Physics

2 answers:

Archy [21]3 years ago

7 0

Answer:

The particles in solids are arranged in a more orderly manner than they are in liquids and gases.

alexandr1967 [171]3 years ago

5 0

The state of matter which has the most orderly arrangement is solid. Here is the order of the three basic states of matter arranged from fastest to slowest, it's better to memorize it :<span>gas, liquid, solid. Also, remember that the colder your solid is, the more ordered it is.</span>

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A medical treatment where the individual breathes in pure oxygen while in a pressurized room or through a tube. This increased p

Leto [7]

Hyperbaric Oxygen Therapy (HBOT) is a medical treatment where the individual breathes in pure oxygen while in a pressurized room or through a tube. The HBOT treatment includes breathing 100% oxygen while under increased atmospheric pressure. It is used <span>for decompression sickness by scuba divers.</span>

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3 years ago

The minute hand of a wall clock measures 16 cm from its tip to the axis about which it rotates. The magnitude and angle of the d

olya-2409 [2.1K]

Answer:

Explanation:

Given

Minute hand length =16 cm

Time at a quarter after the hour to half past i.e. 1 hr 45 min

Angle covered by minute hand in 1 hr is 360 and in 45 minutes 270

$|r|=\frac{3\times 2\pi r}{4}=75.408 cm$

$Angle =270^{\circ}$

(c)For the next half hour

Effectively it has covered 2 revolution and a quarter

$|r|=\frac{2\pi r}{4}=25.136 cm$

angle turned $=90^{\circ}$

(f)Hour after that

After an hour it again comes back to its original position thus displacement is same =25.136

Angle turned will also be same i.e. $90 ^{\circ}$

7 0

3 years ago

Use the drop-down menus to complete each sentence.

qaws [65]

Answer:b

Explanation:

6 0

2 years ago

A 3.0 kg box is sliding along a frictionless horizontal surface with a speed of 1.8 m/s when it encounters a spring. (a) Determi

krok68 [10]

Answer:

a) k = 2231.40 N/m

b) v = 0.491 m/s

Explanation:

Let k be the spring force constant , x be the compression displacement of the spring and v be the speed of the box.

when the box encounters the spring, all the energy of the box is kinetic energy:

the energy relationship between the box and the spring is given by:

1/2(m)×(v^2) = 1/2(k)×(x^2)

(m)×(v^2) = (k)×(x^2)

a) (m)×(v^2) = (k)×(x^2)

k = [(m)×(v^2)]/(x^2)

k = [(3)×((1.8)^2)]/((6.6×10^-2)^2)

k = 2231.40 N/m

Therefore, the force spring constant is 2231.40 N/m

b) (m)×(v^2) = (k)×(x^2)

v^2 = [(k)(x^2)]/m

v = \sqrt{ [(k)(x^2)]/m}

v = \sqrt{ [(2231.40)((1.8×10^-2)^2)]/(3)}

= 0.491 m/s

8 0

2 years ago

Read 2 more answers

PLEASE I REALLY NEED HELP!

Talja [164]

Answer:

$v=\dfrac{1200}{t}\ m/s$

Explanation:

Given that,

The car traveled a total of 1,200 meters during this test.

We need to find the average speed of the car. The average speed of the car is given by total distance covered divided by the time taken. So,

$v=\dfrac{1200}{t}\ m/s$

But putting the value of t we can find the average speed of the car.

3 0

2 years ago