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levacccp [35]
3 years ago
6

7. What mathematical game is played on squares? ______________

Physics
1 answer:
Paha777 [63]3 years ago
3 0

Answer: Dots and boxes, I believe.

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Two workers are sliding 290 kg crate across the floor. One worker pushes forward on the crate with a force of 430 N while the ot
frozen [14]

Answer:

0.285

Explanation:

Given two forces of different magnitude, it is important to note that the product of normal force and coefficient of kinetic friction should be equal to the sum of these two forces at equilibrium. Therefore, this can be Mathematically expressed as:

N/\mu_k=F_1+F_2\\\\

where N is normal force,\mu is coefficient of static friction, F is force and subscripts 1 and 2 represent larger and smaller magnitude forces respectively.  Making \mu the subject of the formula then

\mu_k=\frac{F_1+F_2}{N}

Since normal force N is also given by mg where m is mass of object and g is acceleration due to gravity then substituting N with mg we obtain that

\mu_k=\frac{F_1+F_2}{mg}  and substituting the figures given in the question, taking g as 9.81 we obtain that

\mu_k=\frac { 430 N+380 N}{290\times 9.81}=0.285

Hence,the coefficient of kinetic energy is 0.285 as calculated

4 0
4 years ago
For real gases, how does a change in pressure affect the ratio of pv to nrt?
bogdanovich [222]
At constant temperature and volume the pressure of a gas is directly proportional to the number of moles of the gas. PV =n RT, where R is the universal gas constant. A change in pressure depends with the number of moles of the gas, such that if the number of moles increases then there are many vibrations and collision of the gas molecules with the walls of a container thus increasing the pressure and vice versa.
3 0
3 years ago
Read 2 more answers
As light shines from air to water (n = 1.33) at an incident angle of 45.0 degrees what is the angle of refraction
erma4kov [3.2K]
Using Snell's law
we get
sin(I)/sin(r) = U2/U1
• where U2 represent the water's refractive index and U1 represent air's refractive index
thus
sin45°sin(r) = 1.33/1
1/√2*1.33 = sin(r)
1/1.88 = sin(r)
0.531 = sin(r)
thus the refractive angle is 32°
5 0
3 years ago
The output voltage of a voltage amplifier has been found to decrease by 20% when a load resistance of 1 k is connected. What is
yKpoI14uk [10]

We use the voltage division problem  between the load resistance, amplifier output resistance as

V_{out} = V_{amlifire} \times \frac{R_{load} }{R_{load} + R_{out} }.

Here, V_{out} is the output voltage, V_{amlifire} is the amplifier voltage, R_{load} is the load resistance and R_{out} is the amplifier output resistance.

Therefore,

1-\frac{20}{100} = \frac{1 \ k\Omega }{1 \ k\Omega +R_{out} } \\\\ R_{out} = \frac{1 \ k\Omega }{0.8} -1 \ k\Omega =1250 \Omega -1000 \Omega =250 \Omega.

Thus, the amplifier output resistance is 250 \ \Omega.

4 0
3 years ago
what factors are associated with the advanced performance of japanese students on standardized tests?
Anton [14]

Answer:

Explanation:

honestly

8 0
3 years ago
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