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2 years ago

Which of the following is a product when Na2O and H2O react together? (2 points)

Chemistry

2 answers:

EleoNora [17]2 years ago

8 0

Answer : The correct option is, (c) NaOH

Explanation :

Synthesis reaction : It is chemical reaction in which two or more reactants react together to form a single compound or a product.

$A+B\rightarrow AB$

For example : Formation of sodium chloride salt from sodium and chlorine.

The balanced chemical reaction will be,

$Na_2O+H_2O\rightarrow 2NaOH$

This reaction is a synthesis reaction.

Hence, the product form in this reaction is, NaOH.

TiliK225 [7]2 years ago

5 0

The correct answer is NaOH

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If 90.0 grams of ethane reacted with excess chlorine,how many grams of dicarbon hexachloride would form

tigry1 [53]

Answer:

709 g

Step-by-step explanation:

a) Balanced equation

Normally, we would need a balanced chemical equation.

However, we can get by with a partial equation, as log as carbon atoms are balanced.

We know we will need an equation with masses and molar masses, so let’s <em>gather all the information</em> in one place.

M_r: 30.07 236.74

C₂H₆ + … ⟶ C₂Cl₆ + …

m/g: 90.0

(i) Calculate the moles of C₂H₆

n = 90.0 g C₂H₆ × (1 mol C₂H₆ /30.07 g C₂H₆)

= 2.993 mol C₂H₆

(ii) Calculate the moles of C₂Cl₆

The molar ratio is (1 mol C₂Cl₆/1 mol C₂H₆)

n = 2.993 mol C₂H₆ × (1 mol C₂Cl₆/1 mol C₂H₆)

= 2.993 mol C₂Cl₆

(iii) Calculate the mass of C₂Cl₆

m = 2.993 mol C₂Cl₆ × (236.74 g C₂Cl₆/1 mol C₂Cl₆)

m = 709 g C₂Cl₆

The reaction produces 709 g C₂Cl₆.

6 0

3 years ago

Help :) For 100 points

Iteru [2.4K]

Answer:

6. Color Change.

Production of an odor.

Change of Temperature.

Explanation:

That is the only one I know :)

4 0

2 years ago

Read 2 more answers

Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 9.32 g of ethane is

Pie

Answer:

There will remain 8.06 grams of ethane

Explanation:

Step 1: Data given

Mass of ethane = 9.32 grams

Mass of oxygen = 12.0 grams

Molar mass ethane = 30.07 g/mol

Molar mass oxygen = 32.00 g/mol

Step 2: The balanced equation

2 C2H6 + 7 O2 → 4 CO2 + 6 H2O

Step 3: Calculate moles ethane

Moles ethane = mass ethane / molar mass ethane

Moles ethane = 9.32 grams / 30.07 g/mol

Moles ethane = 0.3099 moles

Step 4: Calculate moles oxygen

Moles oxygen = 12.0 grams / 32.0 g/mol

Moles oxygen = 0.375 moles

Step 5: Calculate the limiting reactant

For 2 moles ethane we need 7 moles O2 to produce 4 moles CO2 and 6 moles H2O

O2 is the limiting reactant. It will completely be consumed ( 0.375 moles)

Ethane is in excess. There will react 2/7 * 0.375 = 0.107 moles

There will remain 0.375 - 0.107 = 0.268 moles

Step 6: Calculate mass ethane

Mass ethane = moles ethane * molar mass ethane

Mass ethane = 0.268 moles * 30.07 g/mol

Mass ethane = 8.06 grams

There will remain 8.06 grams of ethane

7 0

3 years ago

How well can you apply Charles’s law to this sample of gas that experiences changes in pressure and volume? Assume that pressure

anzhelika [568]

Answer:

A: 384

B: 0.85

C: 1.1

D: 221

Explanation:

3 0

3 years ago

Read 2 more answers

QUICK! WILL MARK BRAINLIEST

nalin [4]

Answer:

Ability to be bent = Malleability

Identity = Physical Change

Electrical Current = Conductivity

Dissolve = Solubility

Color, Phase, or Hardness = Physical Property

5 0

3 years ago