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san4es73 [151]
3 years ago
13

Now that you have the knowledge of the highest specific heat capacity and lowest porosity, which material would you choose to bu

ild Rover's new doghouse roof?
Chemistry
2 answers:
Svet_ta [14]3 years ago
7 0

Answer:

Now that you have the knowledge of the highest specific heat capacity and lowest porosity, which material would you choose to build Rover's new doghouse roof?

Oak has the highest heat capacity; therefore, oak can absorb a lot of heat without raising its temperature. This is good for very hot areas. Concrete has the lowest porosity so water will not leak through its pores and drip into the doghouse. This is good for rainy areas. However, clay is second on both lists and might be a good choice overall for hot and rainy weather conditions. Rover should be happy with this.

xXxAnimexXx

Have a great day!

marysya [2.9K]3 years ago
5 0

Answer:

Oak has the highest heat capacity; therefore, oak can absorb a lot of heat without raising its temperature. This is good for very hot areas. Concrete has the lowest porosity so water will not leak through its pores and drip into the doghouse. This is good for rainy areas. However, clay is second on both lists and might be a good choice overall for hot and rainy weather conditions. Rover should be happy with this.

Hope this  helps!

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How salt solution can be determined by using hydrometer​
goldenfox [79]

Answer:

Salt solution may be calculated by measuring the specific gravity of a sample of water using a hydrometer.

<em>Hope</em><em> this</em><em> answer</em><em> correct</em><em> </em><em>(</em><em>^</em><em>^</em><em>)</em><em>.</em><em>.</em><em>.</em><em>.</em>

3 0
3 years ago
At STP, what volume of container would be needed to hold 3.2 moles of gas?
Rzqust [24]

78.4 L volume of container is required to hold 3.2 moles of gas.

Explanation:

  • STP is defined as the standard temperature and pressure of a gas in room temperature conditions. At STP, one mole of the gas which has Avogadro's number of molecules in it will occupy a volume of 22.4 L.
  • So, one mole of a substance or gas will occupy a volume of 22.4 L then the volume of the container needed for  3.2 moles of gas is calculated by multiplying 22.4 L, standard volume with the moles of the gas 3.2 moles.
  • Hence, the answer would be 78.4 L.
3 0
3 years ago
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Katena32 [7]

Answer: Uhm you answered your own question...

Explanation:

7 0
3 years ago
CK-12 Boyle and Charles's Laws if Mrs. Pa pe prepares 12.8 L of laughing gas at 100.0 k Pa and -108 °C and then she force s the
nirvana33 [79]

Answer:

The answer to your question is   P2 = 2676.6 kPa

Explanation:

Data

Volume 1 = V1 = 12.8 L                        Volume 2 = V2 = 855 ml

Temperature 1 = T1 = -108°C               Temperature 2 = 22°C

Pressure 1 = P1 = 100 kPa                    Pressure 2 = P2 =  ?

Process

- To solve this problem use the Combined gas law.

                     P1V1/T1 = P2V2/T2

-Solve for P2

                     P2 = P1V1T2 / T1V2

- Convert temperature to °K

T1 = -108 + 273 = 165°K

T2 = 22 + 273 = 295°K

- Convert volume 2 to liters

                       1000 ml -------------------- 1 l

                         855 ml --------------------  x

                         x = (855 x 1) / 1000

                         x = 0.855 l

-Substitution

                    P2 = (12.8 x 100 x 295) / (165 x 0.855)

-Simplification

                    P2 = 377600 / 141.075

-Result

                   P2 = 2676.6 kPa

3 0
3 years ago
Which is NOT correct for when the silver and vanadium half-cells are connected via a salt bridge and a potentiometer
lidiya [134]

The question is incomplete, the complete question is

Which is NOT correct for when the silver and vanadium half-cells are connected via a salt bridge and a potentiometer? Ag^+ + 1 e^- rightarrow Ag Edegree = 0.7993 V V^2+ + 2e^- right arrow V E degree =-1.125 V Ag+ is reduced V is oxidized 1.924 V V2^+ is reduced Ag is oxidized I and II III, IV, and V I, II, and III III only IV and V

Answer:

only IV and V

Explanation:

If we look at the values of reduction potential for the two species, we will discover that vanadium has a negative reduction potential indicating its tendency towards oxidation.

On the other hand, solve has a positive reduction potential indicating a tendency towards reduction.

This implies that vanadium must be oxidized and silver reduced and not the not her way ground? Hence the answer above.

7 0
3 years ago
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