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daser333 [38]
2 years ago
8

A spring toy jumps up from the floor and comes back down to the floor. Its initial speed is 12 m/s. What is the

Physics
1 answer:
dybincka [34]2 years ago
8 0

Answer:

0\; \rm m \cdot s^{-1}.

Explanation:

In a projectile motion, the kinetic energy (KE) of the projectile is converted to gravitational potential energy (GPE) and then from GPE back to KE.

In this example, the spring toy is the projectile. Refer to the diagram attached.

  • The spring toy started with a velocity of 12\; \rm m\cdot s^{-1}, meaning that its initial KE is non-zero.
  • On the way up, the KE of this spring toy gets converted to GPE.
  • At the top of the trajectory, the GPE of this toy is maximized while its KE is minimized (zero).
  • As the toy returns to the ground, the GPE of this toy gets converted back to KE.
  • The GPE of this toy is zero when the toy is on the ground.

In other words, the kinetic energy (KE) of this toy would be 0 when it is at the top of the trajectory and GPE is maximized.

Since the KE of this toy at the top of the trajectory would be 0, the velocity of this toy at that moment would also be 0\!.

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A 975-kg pickup comes to rest from a speed of 87.5 km/h in a distance of 125 m. Suppose the pickup is initially traveling in the
Savatey [412]

Answer:

A) Force = 2303.925 N in the negative x-direction

B) F ≈ 143998.28 N

C) Ratio = 62.5

Explanation:

A) Since the brakes are the only thing making the van to come to a stop, then first of all, we will calculate the force (in a component along the direction of motion of the car) that the brakes will apply on the van.

Let's find the deceleration using Newton's law of motion formula;

v² = u² + 2as

where;

v = final velocity,

u = initial velocity,

s = displacement

a = acceleration

We are given;

u = 87.5 km/h = 24.3056 m/s

s = 125 m

v = 0 m/s

Thus;

0 = (24.3056)² + 2a(125)

- (24.3056)²= 250a

a = - 24.3056²/250

a = - 2.363 m/s²

Now, force = mass × acceleration

We are given mass = 975 kg

Thus;

Force = 975 x (-2.363)

Force = 2303.925 N in the negative x-direction

B) formula for kinetic energy is

KE = ½mv²

KE = ½(975)(24.3056)²

= 287996.568288 J

Work done on impact = F x 2

Thus;

2F = 287996.568288

F = 287996.568288/2

F ≈ 143998.28 N

C) Ratio = Force on car/braking force = 143998.284/2303.925 = 62.5

3 0
3 years ago
A body of mass 30 kg moving north a velocity of 0.5 ms-1 subjected of 15 N North for 2.7 s.
Ahat [919]

Question: a body of mass 30 kg moving north a velocity of 0.5 ms-1 subjected of 15 N North for 2.7 s.  Calculate the final velocity of the body.

Answer:

14 m/s

Explanation:

From the question,

F = ma......................... Equation 1

make a the subject of the equation

a = F/m....................... Equation 2

Given: F = 15 N, m = 30 kg.

Substitute these values into equation 2

a = 15/3

a = 5 m/s².

Using,

a = (v-u)/t.................... Equation 3

Where v = final velocity, u = initial velocity, t = time.

Given: u = 0.5 m/s, t = 2.7 s and a = 5 m/s²

Substitute these values into equation 3

5 = (v-0.5)/2.7

(v-0.5) = 5×2.7

v-0.5 = 13.5

v = 13.5+0.5

v = 14 m/s

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