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muminat
3 years ago
6

A mixture of N2, O2 and He have mole fractions of 0.25, 0.65, and 0.10, respectively. What is the pressure of N2 if the total pr

essure of the mixture is 3.9 atm?
Chemistry
1 answer:
VladimirAG [237]3 years ago
5 0

Answer:

Partia pressure N₂ → 0.975 atm

Explanation:

Let's analyse the moles fractions:

N₂ → 0.25

O₂ → 0.65

He → 0.1

Partial pressure / Total pressure = Mole fraction

Partial pressure N₂ / 3.9 atm = Mole fraction N₂

Partial pressure N₂ / 3.9 atm = 0.25

Partial pressure N₂ = 3.9 atm . 0.25 → 0.975 atm

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6 0
3 years ago
What is the mass, in grams, of 2.50 * 10-3 mol of aluminum sulfate?
Nonamiya [84]

Answer:

The mass is 0.855 grams (option A)

Explanation:

Step 1: Data given

aluminium sulfate = Al2(SO4)3

Numer of moles Al2(SO4)3 = 2.50 * 10^-3 moles

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atomic mass S = 32.065 g/mol

Atomic mass O = 16 g/mol

Step 2: Calculate molar mass Al2(SO4)3

Molar mass = 2* 26.99 + 3*32.065 + 12*16

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3 years ago
Explain, in detail, how you convert grams of one substance to grams of something else. Be specific and include each step.
VashaNatasha [74]
First you divide the given mass of A (the initial substance) by its molar mass to get its number of moles. Then, based on a balanced chemical reaction, you divide the number of moles by the coefficient of A, then multiply by the coefficient of the product B. Finally, multiply by the molar mass of the product B (if there is a given conversion or yield %, multiply it as well), and this gives the amount of grams of the product.
3 0
3 years ago
Read 2 more answers
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