Answer:
m = 4.5021 kg
Explanation:
given,
Apparent mass of aluminium = 4.5 kg
density of air = 1.29 kg/m³
density of aluminium = 2.7 x 10⁷ kg/m³
true mass of the aluminium = ?
Weight in Vacuum
W = m g
W = ρV g
Air buoyancy acting on aluminium
B = ρ₀V g
Volume is the same in both cases since the volume of the aluminum
displaces an equal amount of volume air.
Apparent weight:
ρV g − ρ₀V g = 4.5 g
ρV − ρ₀V = 4.5

m = ρV


m = 4.5021 kg
Answer:
0.14 J
Explanation:
The maximum velocity is the amplitude times the angular frequency.
vmax = Aω
ω = vmax / A
ω = (3.2 m/s) / (0.06 m)
ω = 53.3 rad/s
For a spring-mass system:
ω = √(k / m)
ω² = k / m
k = ω²m
k = (53.3 rad/s)² (0.050 kg)
k = 142 N/m
The elastic potential energy is:
EE = ½ kx²
EE = ½ (142 N/m) (0.044 m)²
EE = 0.14 J
Answer:
kg m/s
Explanation:
e = Charge = C
V = Voltage = 
c = Speed of light = m/s
Momentum is given by

The unit of MeV/c in SI fundamental units is kg m/s