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ludmilkaskok [199]
3 years ago
14

A ball is dropped from a height of 80m. The time, in seconds, it takes to reach the ground is:__________.

Physics
1 answer:
Aleonysh [2.5K]3 years ago
4 0

Answer:

4.04 s

Explanation:

h = vi + 1/2 a t ^2

HERE  h = 80 m , vi = 0 , a =9.81 m/s^2

80 = 0 + 1/2 × 9.81 × t ^2

80 = 4.905 t^2

t^2 = 80/4.905

t ^2 = 16.30988

t = square root of 16.30988

t =  4.0385 s

t = 4.04 s

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If electrons are taken away from an atom, the atom develops a _________ charge.
VARVARA [1.3K]

Answer:

a positive charge

Explanation:

5 0
4 years ago
Read 2 more answers
Calculate the true mass (in vacuum) of a piece of aluminum whose apparent mass is 4.5000 kg when weighed in air. The density of
sasho [114]

Answer:

m = 4.5021 kg

Explanation:

given,

Apparent mass of aluminium = 4.5 kg

density of air = 1.29 kg/m³

density of aluminium = 2.7 x 10⁷ kg/m³

true mass of the aluminium = ?

Weight in Vacuum

W = m g

W = ρV g

Air buoyancy acting on aluminium

B = ρ₀V g

Volume is the same in both cases since the volume of the aluminum

displaces an equal amount of volume air.

Apparent weight:

ρV g − ρ₀V g = 4.5 g

ρV − ρ₀V = 4.5

V = \dfrac{4.5}{\rho - \rho_0}

m = ρV

m = \dfrac{4.5\times \rho}{\rho - \rho_0}

m = \dfrac{4.5\times 2700}{2700 - 1.29}

m = 4.5021 kg

4 0
3 years ago
Suppose you are conducting an experiment concerning gravity's effects on falling objects, and you want to minimize air resistanc
Vladimir79 [104]
Answer: C) Conduct the experiment in a vacuum.
7 0
3 years ago
A child's toy consists of a spherical object of mass 50 g attached to a spring. One end of the spring is fixed to the side of th
Artemon [7]

Answer:

0.14 J

Explanation:

The maximum velocity is the amplitude times the angular frequency.

vmax = Aω

ω = vmax / A

ω = (3.2 m/s) / (0.06 m)

ω = 53.3 rad/s

For a spring-mass system:

ω = √(k / m)

ω² = k / m

k = ω²m

k = (53.3 rad/s)² (0.050 kg)

k = 142 N/m

The elastic potential energy is:

EE = ½ kx²

EE = ½ (142 N/m) (0.044 m)²

EE = 0.14 J

6 0
3 years ago
Physicists often measure the momentum of subatomic particles moving near the speed of light in units of MeV/c, where c is the sp
maxonik [38]

Answer:

kg m/s

Explanation:

e = Charge = C

V = Voltage = \dfrac{N}{C}m

c = Speed of light = m/s

Momentum is given by

\dfrac{MeV}{c}=\dfrac{e\times V}{c}\\\Rightarrow \dfrac{MeV}{c}=\dfrac{C\times \dfrac{N}{C}\times m}{m/s}\\\Rightarrow \dfrac{MeV}{c}=Ns\\\Rightarrow \dfrac{MeV}{c}=kg\times \dfrac{m}{s}\times s\\\Rightarrow \dfrac{MeV}{c}=kg\cdot m/s

The unit of MeV/c in SI fundamental units is kg m/s

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3 years ago
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