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Charra [1.4K]
2 years ago
12

Problems - Show all work.

Physics
1 answer:
Fittoniya [83]2 years ago
4 0

Answer:

21s

Explanation:

Given parameters;

Radius  = 10m

Speed or velocity  = 3m/s

Unknown:

Period  = ?

Solution:

To solve this problem, use the expression:

      v  = \frac{2\pi r}{T}  

r is the radius

T is the unknown

           Input the parameters and solve for T;

    3  = \frac{2 x \pi  x 10}{T}  

    62.84 = 3T

         T  = 21s

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You push on a box with a force of 300 N directly north. Another person pushes the box with a
tangare [24]

Answer:

resultant \\  \: F =  \sqrt{ {300}^{2} +  {600}^{2}  }  \\  =  \sqrt{450000}  \\  = 670.82 \: newtons

7 0
3 years ago
What is the mechanical advantage of a 8 m ramp that rises 2 m to a stage?
Neko [114]

Answer:

Mechanical advantage = 4

Explanation:

Given the following data;

Distance of effort, de = 8m

Distance of ramp, dr = 2m

To find the mechanical advantage;

Mechanical advantage = de/dr

Substituting into the equation, we have;

Mechanical advantage = 8/2

Mechanical advantage = 4

5 0
2 years ago
A park ranger driving on a back country road suddenly sees a deer in his headlights 20
olya-2409 [2.1K]

Answer:

17.1

Explanation:

The distance ahead, of the deer when it is sighted by the park ranger, d = 20 m

The initial speed with which the ranger was driving, u = 11.4 m/s

The acceleration rate with which the ranger slows down, a = (-)3.80 m/s² (For a vehicle slowing down, the acceleration is negative)

The distance required for the ranger to come to rest, s = Required

The kinematic equation of motion that can be used to find the distance the ranger's vehicle travels before coming to rest (the distance 's'), is given as follows;

v² = u² + 2·a·s

∴ s = (v² - u²)/(2·a)

Where;

v = The final velocity = 0 m/s (the vehicle comes to rest (stops))

Plugging in the values for 'v', 'u', and 'a', gives;

s = (0² - 11.4²)/(2 × -3.8) = 17.1

The distance the required for the ranger's vehicle to com to rest, s = 17.1 (meters).

6 0
3 years ago
If I was to build a functioning Scale Model of a dam, what would I need?
anyanavicka [17]
You will need rocks brick and water.
8 0
3 years ago
A person exerts a 19-N force on a cart attached to a spring and holds the cart steady. The cart is displaced 0.060 m from its eq
Mariana [72]

To solve this problem, apply the concepts related to Hooke's law. From there we will find the spring constant. Subsequently, applying Energy balance, which includes gravitational potential energy, elastic potential energy and kinetic energy, we will bury the system's energy. Finally, using the displacement expression for the simple harmonic movement, we will find the expression that describes the system.

PART A) The expression for the spring force is

F=kx

Here,

k = Spring constant

x = Displacement

Rearranging to find the spring constant we have that

k = \frac{F}{x}

k = \frac{19}{0.06}

k = 316.66N/m \approx 320N/m

PART B ) The gravitational potential energy acts on the spring holds the cart is zero. Since cart is placed in the equilibrium position. The kinetic energy of the cart is zero.  Therefore the expression for the total energy is,

E = (PE)_g+(PE)_{spring}+KE

E = 0+\frac{1}{2} kx^2+0

E = \frac{1}{2} (316.66N/m)(0.06)^2

E = 0.569J \approx 0.57J

PART C) The expression for the angular frequency is

\omega = 2\pi f

\omega = 2\pi (1Hz)

\omega = 2\pi rad/s

The equation for the motion of the cart is

x(t)= Acos(\omega t)

Replacing,

x(t) = 0.06 cos (2\pi t)

5 0
3 years ago
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