Explanation:
1) Based on the octet rule, iodine form an <u>I</u>⁻ ion.
Therefore,
Option E is correct ✔
2) The electronic configuration of the sulfide ion (S²⁻) is :
₁₆S = 1s² 2s² 2p⁶ 3s² 3p⁴ or [Ne] 3s² 3p⁴
₁₈S²⁻ = 1s² 2s² 2p⁶ 3s² 3p⁶ or [Ne] 3s² 3p⁶
Therefore,
Option E is correct ✔
3) valence shell electron of
Halogens = 7
Alkali metal = 1
Alkaline earth metal = 2
Therefore,
Option D is correct ✔
4) Group 2 element lose two electron in order to achieve Noble gas configuration.
And here Group 2 element is Sr
Therefore,
Option B is correct ✔
5) Group 13 element lose three electron in order to achieve Noble gas configuration.
And here Group 13 element is Al
Therefore,
Option B is correct ✔
6) For a given arrangements of ions, the lattice energy increases as ionic radius <u>decreases</u> and as ionic charge <u>increases</u>.
Therefore,
Option A is correct ✔
Answer:
Hello
Explanation:
tbh YES and it sucks bc ppl treat u like trash, but don't let that get into ur head just be you, you'll find someone who treats u as if u were literally a goddess, keep ur head up and dont worry.
your welcome! ^^
Answer : The correct statement is:
The density of each piece is the same as that of the original block.
Explanation :
Intensive property : It is defined as a property of substance which does not change as the amount of substance changes.
Examples: Temperature, refractive index, density, hardness, etc.
According to question, if Ana has a block made of pure gold and she cuts this block into two equal pieces then the density of each piece is the same as that of the original block because density is an intensive property that does not changes until and unless material is changed.
That means density remains same as that of the original piece.
Hence, the correct statement is the density of each piece is the same as that of the original block.
Answer:
\left \{ {{y=206} \atop {x=82}}Pb \right.
Explanation:
isotopes are various forms of same elements with different atomic number but different mass number.
Radioactivity is the emission of rays or particles from an atom to produce a new nuclei. There are various forms of radioactive emissions which are
- Alpha particle emission \left \{ {{y=4} \atop {x=2}}He \right.
- Beta particle emission \left \{ {{y=0} \atop {x=-1}}e \right.
- gamma radiation \left \{ {{y=0} \atop {x=0}}γ \right.
in the problem the product formed after radiation was Pb-206. isotopes of lead include Pb-204, Pb-206, Pb-207, Pb-208. they all have atomic number 82. which means the radiation cannot be ∝ or β since both radiations will alter the atomic number of the parent nucleus.
Only gamma radiation with \left \{ {{y=0} \atop {x=0}}γ \right. will produce a Pb-206 of atomic number 82 and mass number 206 , since gamma ray have 0 mass and has 0 atomic number.equation is shown below
\left \{ {{y=206} \atop {x=82}}Pb\right ⇒ \left \{ {{y=206} \atop {x=82}}Pb\right + \left \{ {{y=0} \atop {x=0}}γ\right.
Thus the atomic symbol is \left \{ {{y=206} \atop {x=82}}Pb\right
