The correct option is C.
The pitch of a string refers to the quality of sound that is produced by the string when it vibrates. There are three basic factors that affect the quality of pitch of a string, these are: the tension, the thickness of the string and the length of the string. The higher the thickness of the string, the lower the pitch of the string, thus, increasing the thickness of the string will lower the pitch.
The moles of HCl to neutralize the sodium hydroxide produced is<u> 0.0135 mole. </u>
Neutralization or neutralization is a chemical response wherein an acid and a base react quantitatively with each other. In a reaction in water, neutralization outcomes in there being no excess of hydrogen or hydroxide ions gift in the answer.
<u>calculation:-</u>
<u />
2Na + 2H₂O -----> 2NaOH + H₂
2 mol or 46g of Na produces 80 grams of NaOH
∴ 0.31 g of Na will produce = 80/46 × 0.31
= 0.54 gram of NaOH.
mol of NaOH = 0.54/40
= 0.0135
Since both Hcl and NaOH have the same valance factor,
1 mole NaOH is needed to neutralize 1 mol HCl
∴ 0.0135 mole of NaOH will need = 0.0135 mole of HCl
mass = 0.0135 × 36.5
=<u> 0.493 grams of HCL.</u>
Learn more about neutralizing here:-brainly.com/question/23008798
#SPJ4
Answer: The enthalpy change for formation of butane is -125 kJ/mol
Explanation:
The balanced chemical reaction is,
The expression for enthalpy change is,
![\Delta H=[n\times H_f{products}]-[n\times H_f{reactants}]](https://tex.z-dn.net/?f=%5CDelta%20H%3D%5Bn%5Ctimes%20H_f%7Bproducts%7D%5D-%5Bn%5Ctimes%20H_f%7Breactants%7D%5D)
Putting the values we get :
![\Delta H=[4\times H_f_{CO_2}+5\times H_f_{H_2O}]-[1\times H_f_{C_4H_{10}}+\frac{13}{2}\times H_f_{O_2}]](https://tex.z-dn.net/?f=%5CDelta%20H%3D%5B4%5Ctimes%20H_f_%7BCO_2%7D%2B5%5Ctimes%20H_f_%7BH_2O%7D%5D-%5B1%5Ctimes%20H_f_%7BC_4H_%7B10%7D%7D%2B%5Cfrac%7B13%7D%7B2%7D%5Ctimes%20H_f_%7BO_2%7D%5D)
![-2877=[(4\times -393)+(5\times -286)]-[1\times H_f_{C_4H_{10}}+\frac{13}{2}\times 0]](https://tex.z-dn.net/?f=-2877%3D%5B%284%5Ctimes%20-393%29%2B%285%5Ctimes%20-286%29%5D-%5B1%5Ctimes%20H_f_%7BC_4H_%7B10%7D%7D%2B%5Cfrac%7B13%7D%7B2%7D%5Ctimes%200%5D)
Thus enthalpy change for formation of butane is -125 kJ/mol
Answer:
Option D. 5.5
Explanation:
The equation is this:
2A + 6B ⇒ 3C
With the amounts that we were given, let's determine which is the <em>limting reactant</em>
2 A reacts with 6 B
4 A will react with ( 4 .6)/2 = 12B
I have 11 B, so the limiting is B
6 B react with 2 A
11 B will react with (11 .2 )/6 =3.66 A
I have 4 A, so A is the excess.
6 B produce 3 C
11 B will produce ( 11 .3)/6 = 5.5C
Answer:
removes the fertile B horizon of soil
Explanation:
<em>Wind erosion has the capacity to remove the fertile B horizon of the soil.</em>
The term wind erosion generally refers to the capacity of high-magnitude wind to cause damages to the terrestrial environment. Soils can get their topmost layers removed by a strong wind if there are no barriers such as vegetation to break the speed of the wind.
The topmost layers in most cases consist of humus and the fertile minerals from parent materials. When the topmost layer is lost, the soil becomes unproductive for agriculture.
