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Sophie [7]
3 years ago
9

You were hoping to receive a scholarship for volleyball and are entering your personal information and statistics on a secure we

bsite to be reviewed by recruiters the website requires that you report your height in feet and inches to the nearest 1/4 of an inch you have a decimal tape measure and find that you were 5.89 feet tall what height measurement will you report in order to honestly and accurately report your height
Engineering
2 answers:
AfilCa [17]3 years ago
8 0

Answer:

5 feet + 11 inches

Explanation:

given data

tall = 5.89 feet  =

1 feet = 12 inches

solution

we will convert given 5.89 feet as

5.89 feet = 5 feet + 0.89 feet  .............1

so now we need convert  0.89 feet  into inch

so we know

\frac{1}{12} =\frac{0.89}{a}  

solve we get a

a = 0.89 × 12

a = 10.68 inches

so from equation 1

5.89 feet = 5 feet + 10.68 inches

5.89 feet =  5 feet + 11 inches

kozerog [31]3 years ago
6 0
I think it is fair to say 5 and 3/4 inches.
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Mike is involved in developing the model building codes that various states and local authorities in the United States adopt. He
Lyrx [107]
<h3>Answer:</h3>

Mike is involved in developing the model building codes that various states and local authorities in the United States adopt. He works with the <u>Workers</u> , which consists of members who are building code officials and building safety professionals.

8 0
2 years ago
Which type of system is being researched to deliver power to several motors to drive multiple systems in vehicles?
qaws [65]

Answer:

pneumatic power system

Explanation:

pneumatic power can be used to quietly operate power windows, door locks, power mirrors, and much much more, also negative pressure pneumatics (vacuum) is used to control many engine and fuel systems

8 0
2 years ago
How much does it cost to replace a roof on a 2,200 square foot house.
Norma-Jean [14]

Answer:

An estimated amount of $8,200 to $12,000

Explanation:

~~It all really depends on what materials you have purchased for the replacement.

~~If you're to choose lower-quality materials the cost would be less but high-quality ones will be more expensive.

(The answer is if you're most likely to purchase asphalt shingles)

Hope this Helps!

7 0
2 years ago
Which of the following is described as a way engineers can test and investigate how things should be under certain circumstances
goblinko [34]

Answer:

The option that is best described as a way engineers can test and investigate how things should be under certain circumstances is;

  • Modeling

Explanation:

Modeling is a tool an engineer can use for the physical representation of a system that will facilitate the definition, testing and analysis, communication, data generation, data verification and data validation of given concepts

Models also aid in setting specifications, supporting designs, and verification of a given system

Therefore, with modeling engineers can investigate the behavior of systems under given environmental conditions.

3 0
3 years ago
A commuter train traveling at 50 mi/h is 3 mi from a station. The train then decelerates so that its speed is 15 mi/h when it is
jonny [76]

Answer:

a) t = 277.477\,s\,(4.625\min), b) v_{f} = 0\,\frac{mi}{h}, c) a = -0.128\,\frac{ft}{s^{2}}

Explanation:

a) The deceleration experimented by the commuter train in the first 2.5 miles is:

a=\frac{[(15\,\frac{mi}{h} )\cdot (\frac{5280\,ft}{1\,mi} )\cdot (\frac{1\,h}{3600\,s} )]^{2}-[(50\,\frac{mi}{h} )\cdot (\frac{5280\,ft}{1\,mi} )\cdot (\frac{1\,h}{3600\,s} )]^{2}}{2\cdot (2.5\,mi)\cdot (\frac{5280\,ft}{1\,mi} )}

a = -0.185\,\frac{ft}{s^{2}}

The time required to travel is:

t = \frac{(15\,\frac{mi}{h} )\cdot (\frac{5280\,ft}{1\,fi} )\cdot(\frac{1\,h}{3600\,s} )-(50\,\frac{mi}{h} )\cdot (\frac{5280\,ft}{1\,fi} )\cdot(\frac{1\,h}{3600\,s} )}{-0.185\,\frac{ft}{s^{2}} }

t = 277.477\,s\,(4.625\min)

b) The commuter train must stop when it reaches the station to receive passengers. Hence, speed of train must be v_{f} = 0\,\frac{mi}{h}.

c) The final constant deceleration is:

a = \frac{(0\,\frac{mi}{h} )\cdot (\frac{5280\,ft}{1\,mi} )\cdot(\frac{1\,h}{3600\,s} )-(15\,\frac{mi}{h} )\cdot (\frac{5280\,ft}{1\,mi} )\cdot(\frac{1\,h}{3600\,s} )}{(2.875\,min)\cdot (\frac{60\,s}{1\,min} )}

a = -0.128\,\frac{ft}{s^{2}}

7 0
3 years ago
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