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Sophie [7]
3 years ago
9

You were hoping to receive a scholarship for volleyball and are entering your personal information and statistics on a secure we

bsite to be reviewed by recruiters the website requires that you report your height in feet and inches to the nearest 1/4 of an inch you have a decimal tape measure and find that you were 5.89 feet tall what height measurement will you report in order to honestly and accurately report your height
Engineering
2 answers:
AfilCa [17]3 years ago
8 0

Answer:

5 feet + 11 inches

Explanation:

given data

tall = 5.89 feet  =

1 feet = 12 inches

solution

we will convert given 5.89 feet as

5.89 feet = 5 feet + 0.89 feet  .............1

so now we need convert  0.89 feet  into inch

so we know

\frac{1}{12} =\frac{0.89}{a}  

solve we get a

a = 0.89 × 12

a = 10.68 inches

so from equation 1

5.89 feet = 5 feet + 10.68 inches

5.89 feet =  5 feet + 11 inches

kozerog [31]3 years ago
6 0
I think it is fair to say 5 and 3/4 inches.
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Unit for trigonometric functions is always "radian". 1. 10 points: Do NOT submit your MATLAB code for this problem (a) Given f(x
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Below is the required code.

Explanation:

%% Newton Raphson Method

clear all;

clc;

x0=input('Initial guess:\n');

x=x0;

f=exp(-x)-sin(x)-0.2;

g=-exp(-x)-cos(x);

ep=10;

i=0;

cc=input('Condition of convergence:\n');

while ep>=cc

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fprintf('x = %6f and error = %6f at iteration = %2f \n',x,ep,i);

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fprintf('The solution x = %6f \n',x);

%% End of MATLAB Program

Command Window:

(a) First Root:

Initial guess:

1.5

Condition of convergence:

0.01

x = -1.815662 and error = 3.315662 at iteration = 1.000000

x = -0.644115 and error = 1.171547 at iteration = 2.000000

x = 0.208270 and error = 0.852385 at iteration = 3.000000

x = 0.434602 and error = 0.226332 at iteration = 4.000000

x = 0.451631 and error = 0.017029 at iteration = 5.000000

x = 0.451732 and error = 0.000101 at iteration = 6.000000

The solution x = 0.451732

>>

Second Root:

Initial guess:

3.5

Condition of convergence:

0.01

x = 3.300299 and error = 0.199701 at iteration = 1.000000

x = 3.305650 and error = 0.005351 at iteration = 2.000000

The solution x = 3.305650

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(b) Guess x=0.5:

Initial guess:

0.5

Condition of convergence:

0.01

x = 0.450883 and error = 0.049117 at iteration = 1.000000

x = 0.451732 and error = 0.000849 at iteration = 2.000000

The solution x = 0.451732

>>

Guess x=1.75:

Initial guess:

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Condition of convergence:

0.01

x = 227.641471 and error = 225.891471 at iteration = 1.000000

x = 218.000998 and error = 9.640473 at iteration = 2.000000

x = 215.771507 and error = 2.229491 at iteration = 3.000000

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x = 216.703197 and error = 0.989439 at iteration = 5.000000

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x = 216.971251 and error = 0.000813 at iteration = 7.000000

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Initial guess:

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0.01

x = 3.309861 and error = 0.309861 at iteration = 1.000000

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Guess x=4.7:

Initial guess:

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Explanation:

The two solutions are x =0.451732 and 3.305651 within the range 0 < x< 5.

The initial guess x = 1.75 fails to determine the solution as it's not in the range. So the solution turns to unstable with initial guess x = 1.75.

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