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zheka24 [161]
2 years ago
12

Please Help! A ball is thrown straight up from the ground. What way does its acceleration point at the top?

Physics
1 answer:
QveST [7]2 years ago
3 0

Answer: A. Vertical

Explanation:

If the ball is thrown straight up from the ground (asuming the ground as height 0), this means its initial velocity is greater than zero.

While the ball rises and gains height, its velocity decreases until it reaches its maximum height where it stops (velocity equal to zero) and then it begins to fall to the ground.

Now, <u>during all the movement, the ball has an acceleration</u>, which is the acceleration due gravity (9.8 m/s^{2}  on Earth), even at the top or maximum height (when the ball stops just for fraction of time), and this acceleration points vertical and downward to the Earth's center.

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Question 30
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Answer: 0.69\°

Explanation:

The angular diameter \delta of a spherical object is given by the following formula:

\delta=2 sin^{-1}(\frac{d}{2D})

Where:

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D=1338 m is the distance to the spherical object

Hence:

\delta=2 sin^{-1}(\frac{16 m}{2(1338 m)})

\delta=0.685\° \approx 0.69\° This is the angular diameter

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What force is needed to accelerate a 0.5kg football at a rate of 40m/s
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f= 0.5 x40
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