A person is trying to lift a crate that has a mass of 30 kg. The normal force of the floor is currently supplying 150 N of force
2 answers:
Answer:
The exerting force by the person is 294 N.
(3) is correct option.
Explanation:
Given that,
Mass of crate = 30 kg
Normal force = 150 N
When a person is lifting a crate then the crate does not contact the floor
So, the normal force is zero.
We need to calculate the exerting force by the person
Using formula of force
Hence, The exerting force by the person is 294 N.
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Answer:
r = 0.05 m = 5 cm
Explanation:
Applying ampere's law to the wire, we get:
where,
r = distance of point P from wire = ?
μ₀ = permeability of free space = 4π x 10⁻⁷ N/A²
I = current = 2 A
B = Magnetic Field = 8 μT = 8 x 10⁻⁶ T
Therefore,
<u>r = 0.05 m = 5 cm</u>
Answer:
Force on front axle = 6392.85 N
Force on rear axle = 8616.45 N
Explanation:
As we know that the weight of the car is balanced by the normal force on the front wheel and rear wheels
Now we know that
now we know that distance between the axis is 2.70 m and centre of mass is 1.15 m behind front axle
so we can write torque balance about its center of mass
now from above equation
now we have
now the other force is given as