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MArishka [77]
3 years ago
6

A person is trying to lift a crate that has a mass of 30 kg. The normal force of the floor is currently supplying 150 N of force

. How much force is the person currently exerting?
144

150

294

294
Physics
2 answers:
pochemuha3 years ago
8 0

5 meters per second

frez [133]3 years ago
6 0

Answer:

The exerting force by the person is 294 N.

(3) is correct option.

Explanation:

Given that,

Mass of crate = 30 kg

Normal force = 150 N

When a person is lifting a crate then the crate does not contact the floor

So, the normal force is zero.

We need to calculate the exerting force by the person

Using formula of force

F = ma

F=30\times9.8

F=294\ N

Hence, The exerting force by the person is 294 N.

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A rope with a mass density of 1 kg/m has one end tied to a vertical support. You hold the other end so that the rope is horizont
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v' = 2.83 m/s

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also we know that linear mass density is given as

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so the velocity is given as

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If an object has a fast velocity, the dots on a ticker tape diagram will be _____.
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If an object has a fast velocity, the dots on a ticker tape diagram will be far apart.

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A resonant circuit using a 286-nFnF capacitor is to resonate at 18.0 kHzkHz. The air-core inductor is to be a solenoid with clos
lukranit [14]

Answer:

The inductor contains N = 523962.32 loops  

Explanation:

From the question we are told that

     The capacitance of the capacitor is  C =  286nF = 286 * 10^{-9} \  F

      The resonance frequency is  f = 18.0 kHz =  18*10^{3} Hz

       The diameter is  d =  1.1 mm = \frac{1.1 }{1000} = 0.00011 \ m

       The  of the air-core inductor is l = 12 \ m

        The permeability of free space is  \mu_o = 4 \pi *10^{-7} \ T \cdot m/A

 

Generally the inductance of this air-core inductor is mathematically represented as

              L =  \frac{\mu_o * N^2 \pi d^2}{4 l}

This inductance can also be mathematically represented as

               L = \frac{1}{w^2}

Where w is the angular speed mathematically given as

             w = 2 \pi f

So

            L =  \frac{1}{4 \pi ^2 f^2}

Now equating the both formulas for inductance

         \frac{\mu_o * N^2 \pi d^2}{4 l}  =  \frac{1}{4 \pi ^2 f^2}

making N the subject of  the formula

              N = \sqrt{\frac{1}{(2 \pi f)^2} * \frac{4 * l }{\mu_o * \pi d^2 C}  }

              N =  \frac{1}{2 \pi f} * \frac{2}{d} * \sqrt{\frac{l}{\pi * \mu_o * C} }

             

 Substituting value

            N =  \frac{1}{ 3.142  * 18*10^{3} * 0.00011 }  \sqrt{\frac{12}{ 3.142  * 4 \pi *10^{-7}* 286 *10^{-9}} }

              N = 523962.32 loops  

4 0
3 years ago
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