Answer:
Explanation:
initial velocity u = 32.7 m /s
final velocity v = 50.3 m /s
displacement s = 44500 m
acceleration a = ?
v² = u² + 2 a s
50.3² = 32.7² + 2 x a x 44500
2530.09 = 1069.29 + 89000a
a .016 m /s²
time taken t = ?
v = u + at
50.3 = 32.7 + .016 t
t = 1100 s
Answer:
The true weight of the aluminium is
4.5021 kg
Explanation:
Given data
= 4.5 kg
= 1.29 ![\frac{kg}{m^{3} }](https://tex.z-dn.net/?f=%5Cfrac%7Bkg%7D%7Bm%5E%7B3%7D%20%7D)
= 2.7× ![10^{3} \frac{kg}{m^{3} }](https://tex.z-dn.net/?f=10%5E%7B3%7D%20%5Cfrac%7Bkg%7D%7Bm%5E%7B3%7D%20%7D)
The true mass of the aluminium is given by
![m_{alu} = \frac{\rho_{alu}m_{app}}{\rho_{alu} -\rho_{air} }](https://tex.z-dn.net/?f=m_%7Balu%7D%20%3D%20%5Cfrac%7B%5Crho_%7Balu%7Dm_%7Bapp%7D%7D%7B%5Crho_%7Balu%7D%20-%5Crho_%7Bair%7D%20%7D)
Put all the values in above equation we get
![m_{alu} = \frac{(2700)(4.5)}{2700-1.29}](https://tex.z-dn.net/?f=m_%7Balu%7D%20%3D%20%5Cfrac%7B%282700%29%284.5%29%7D%7B2700-1.29%7D)
4.5021 kg
Therefore the true weight of the aluminium is
4.5021 kg
Answer:
C
Explanation:
got a one hundred on the test
Explanation:
Fluids exert both drag and lift forces on moving objects. Drag is the frictional force opposing motion. Lift is the force perpendicular to motion.
Some objects, like parachutes, are designed with large cross sectional areas to increase drag force. Usually though, objects are designed to minimize drag force. It's why cars, planes, and boats have sleek shapes.
Airplane wings have shapes called airfoils that generate lift. It's what makes them fly. The same shape is found in racecar spoilers. These spoilers use lift force to push down on the rear tires, increasing traction.
Perpendicular slope would be 1/3. so the equation will be Y=1/3x -4