<span>The core finally cools into a white dwarf, then a black dwarf. This is what happens when a normal-sized star dies. If a really huge star dies, it has so much mass that after the helium is used up, it still has enough carbon to fuse it into heavy elements like iron. When the core turns to iron, it no longer burns.
please give me </span>Brainliest answer?
The answer is B.)
This is because for years scientists have build up and found discoveries that led to recent discoveries brought by previous scientists.
Hope this helps
Answer:
To the right relative to the original frame.
Explanation:
In first reference frame <em>S</em>,
Spatial interval of the event, 
Temporal interval of the event, 
In the second reference frame <em>S'</em>, the two flashes are simultaneous, which means that the temporal interval of the event in this frame is 
The speed of the frame <em>S' </em>with respect to frame <em>S</em> = v.
According to the Lorentz transformation,
And positive v means the velocity of the second frame<em> </em><em>S'</em> is along the positive x-axis direction, i.e., to the right direction relative to the original frame <em>S</em>.
An estimated value for gravity at a distance r from the middle of the Earth can be gotten by supposing that the Earth's density is spherically symmetric. The gravity hinge on only on the mass inside the sphere of radius r. All the assistances from outside cancel out as a fall out of the inverse-square law of gravitation. Another result is that the gravity is the same as if all the mass were concentrated at the midpoint. Therefore, the gravitational acceleration at this radius is
g(r) = GM(r) / r²
M(r) = mass enclosed by radius r.
If the Earth had a continual density ρ, the mass would be M(r) = (4/3)πρr³ and the dependence of gravity on distance would be
g(r) = (4/3)πGρr
G = 6.674e-11 m³/kgs²
Answer:
V = 575.6 Volts
Explanation:
As we know that surface area of the equi-potential surface is given as
so we will say
Now the potential due to a point charge is given as
