Answer: 0.455 m/s^2
Explanation:
f = ma = m x 9.8=689 (the mass is constant)
m = 78.3
now on the elevator
f = 721 = m x a
a= 10.26
the elevator is moving down because there is a increase in weight. the acceleration of elevator = 10.26-9.8 = 0.455
Short distance to turn the circumference of the wheels. Mechanical advantage is load/effort I think
Answer:
i) No, the spring scale does not read a different value
ii) The torque will read a different value, it will reduce
iii) The spring scale does not need to be measured at the center of mass location.
Explanation:
The torque caused by the gyroscope can be given by the relation,
r × f

The torque measured by the gyroscope varies directly with the distance, r.
A decrease in the distance r will also cause a decrease in the value of the torque measured. When the distance, r is reduced from 7.5 inches to 5 inches, the torque caused by the gyroscope's weight also reduces.
The weight of the gyroscope remains constant despite the reduction in the distance because the weight of the gyroscope is not a function of the distance from the gyroscope. Therefore, the spring scale will not read a different value.
Yes, the spring scale does not need to be measured from the center of mass location because the weight does not depend on the location of measurement. The reading of the sprig scale remains constant.
Answer:
Her angular speed (in rev/s) when her arms and one leg open outward is 
Explanation:
Initial moment of inertia when arms and legs in is 
Final moment of inertia when her arms and on leg open outward, 
Initial angular speed 
Let the final angular speed be 
Since external torque on her is zero so we can apply conservation of angular momentum

=>
=>
Thus her angular speed (in rev/s) when her arms and one leg open outward is 
Answer:
V = 0.69 m/s
Explanation:
Given that,
The mass of a ice skater, m₁ = 32 kg
The initial speed of the ice skater, u₁ = 0
Mass of a snowball, m₂ = 0.5 kg
The initial speed of a snowball, u₂ = 45 m/s
eIt is mentioned that the collision is totally inelastic. Let V be the common speed of skater and the ball. So, using the law of conservation of momentum.

So, the common speed is equal to 0.69 m/s.