Answer: They can be apllied to the senario he can pettition or he can use bigger bags those are just a couple of ideas.
Answer:
This reaction is spontaneous for temperature lower than 3722.1 Kelvin or 3448.95 °C
Explanation:
<u>Step 1: </u>Data given
ΔH = −320.1 kJ/mol
ΔS = −86.00 J/K · mol.
<u>Step 2:</u> Calculate the temperature
ΔG<0 = spontaneous
ΔG= ΔH - TΔS
ΔH - TΔS <0
-320100 - T*(-86) <0
-320100 +86T < 0
-320100 < -86T
320100/86 > T
3722.1 > T
The temperature should be lower than 3722.1 Kelvin (= 3448.9 °C)
We can prove this with Temperature T = 3730 K
-320100 -3730*(-86) <0
-320100 + 320780 = 680 this is greater than 0 so it's non spontaneous
T = 3700 K
-320100 -3700*(-86) <0
-320100 + 318200 = -1900 this is lower than 0 so it's spontaneous
The temperature is quite high because of the big difference between ΔH and ΔS.
This reaction is spontaneous for temperature lower than 3722.1 Kelvin or 3448.95 °C
Answer:
the volume of the gas at 2.50 atm pressure is equal to 1.44 Litres.
Explanation:
<span>the answer is c. energy</span>
