ThIs is the same type of problem
find out the time value
3 = 1/2*a*T^2
6/10 = t^2
t = 0.77 seconds
and the distance is given 5 m
thus speed ,= distance/time
speed = 5/0.77
= 6.45 m/s
Answer:
Therefore the the highest frequency is 620Hz and lowest frequency is 580Hz
Explanation:
Given data
Source Frequency fs=600Hz
Length r=1.0m
RPM=100 rpm
The speed of the generator is calculated as:

Substitute the given values

For approaching generator the frequency is calculated as:

On the other hand,for the receding generator,Doppler's effect is expressed as:

Therefore the the highest frequency is 620Hz and lowest frequency is 580Hz
Answer:10m/s
Explanation:
Wave speed ,v=for
Where π= wavelength=2m
Period =1/f f=frequency of wave
F=1/period
=1/0.2=5Hz
So speed of waves,v=5×2=10m/s
<span>According to Newton's first law of motion:
-- objects at rest will remain at rest unless acted upon by an outside force
-- objects in motion will remain in motion unless acted upon by an outside force
</span>
Answer:
Hope it helps for you :)))))