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Yanka [14]
3 years ago
15

What happens when light bounces off an object

Physics
2 answers:
photoshop1234 [79]3 years ago
7 0

<span>
<span>When light bounces off an object, it either gets absorbed, or reflected. For example, light can get absorbed on surfaces which are black in color and they can reflect from flat surfaces such as a mirror. It all matters on the angle of incidence. The angle of incidence is also known as the angle of reflection.</span></span>

<span><span /></span><span> Angle of reflection = Angle of incidence</span>

<span /><span>T<span><span>he ray of light approaching the mirror is called the incident ray. The ray of light that leaves the mirror is called the reflected ray.   </span></span></span>

<span><span><span>Hope it helps </span> </span></span>

Sever21 [200]3 years ago
3 0
Absorbtion consists of when light strikes on an object and bounces off. 
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spotlight on a boat is 2.5 m above the water, and the light strikes the water at a point that is 8.0 m horizontally displaced fr
ludmilkaskok [199]

Answer:

Explanation:

Let i be the angle of incidence and r be the angle of refraction .

From the figure

Tan ( 90 - i ) = 2.5 / 8

cot i = 2.5 / 8

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i = 72.65°

From snell's law

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sin 72.65 / sinr = 1.333

sin r = .9545  / 1.333

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r = 46⁰

From the figure

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3 0
3 years ago
Heights of men on a baseball team have a​ bell-shaped distribution with a mean of 166 cm 166 cm and a standard deviation of 5 cm
kaheart [24]

Answer:

95 %

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\mu = 166 cm = Mean

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a) 156 cm and 176 cm

166-5\times 2=156

166+5\times 2=176

From the empirical rule 95% of all values are within 2 standard deviation of the mean, so about 95% of men are between 156 cm and 176 cm.

b) 151 cm and 181 cm

166-5\times 3 =151

166+5\times 3=181

The empirical rule tells us that about 99.7% of all values are within 3 standard deviations of the mean, so about 99.7% of men are between 151 cm and 181 cm.

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3 years ago
A pulsar is a rapidly rotating neutron star that emits a radio beam the way a lighthouse emits a light beam. We receive a radio
DanielleElmas [232]

Answer:

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Putting all together:

\alpha =\frac{\frac{2\pi}{T_f}-\frac{2\pi}{T_i}}{\Delta t}=\frac{2\pi}{\Delta t}(\frac{1}{T_f}-\frac{1}{T_i})

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8 0
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katen-ka-za [31]

Answer:

The property of the wave marked X is related to the source of the wave

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