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Komok [63]
3 years ago
8

The absolute temperature of a fixed mass of ideal gas is tripled while its volume remains constant. The ratio of the final press

ure of the gas to its initial pressure is
Chemistry
1 answer:
olga_2 [115]3 years ago
7 0

Answer:

3 : 1

Explanation:

The following data were obtained from the question:

Initial temperature (T₁) = T

Initial pressure (P₁) = P

Final temperature (T₂) = 3T

Final pressure (P₂) =..?

Since the volume is constant, we shall use the following formula P₁ /T₁ = P₂ /T₂ to obtain the final pressure. This is illustrated below:

P₁ /T₁ = P₂ /T₂

P/T = P₂ /3T

Cross multiply

T × P₂ = P × 3T

Divide both side by T

P₂ = P × 3T /T

P₂ = P × 3

P₂ = 3P

Therefore, the final pressure is tripled.

Finally, we shall determine the ratio of the final pressure to the initial pressure as follow:

Initial pressure (P₁) = P

Final pressure (P₂) = 3P

Final pressure (P₂) : Initial pressure (P₁)

P₂ : P₁ => 3P/P

P₂ : P₁ => 3 : 1

Therefore, the ratio of the final pressure to the initial pressure is 3 : 1

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A piece of sodium metal can be described as?
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Which of the following is altered by a catalyst?
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The following reaction produces ethanoic acid (CHACOOH) from methanol (CH3OH) and carbon
tigry1 [53]

Answer:

\boxed{\text{300 g}}

Explanation:

We will need a balanced chemical equation with masses and molar masses, so, let's gather all the information in one place.

M_r:         32                          60

           CH₃OH + CO ⟶ CH₃COOH

m/g:        160

(a) Moles of CH₃OH

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(b) Moles of CH₃COOH

\text{Moles of CH$_{3}$COOH} = \text{5.00 mol CH$_{3}$OH } \times \dfrac{\text{1 mol CH$_{3}$COOH}}{\text{1 mol CH$_{3}$OH }} = \text{5.00 mol CH$_{3}$COOH}

(c) Mass of CH₃COOH

\text{Mass of CH$_{3}$COOH} =\text{5.00 mol CH$_{3}$COOH} \times \dfrac{\text{60 g CH$_{3}$COOH}}{\text{1 mol CH$_{3}$COOH}} = \textbf{300 g CH$_{3}$COOH}\\\\\text{The maximum mass of ethanoic acid that can be produced is $\boxed{\textbf{300 g}}$}

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3 years ago
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