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Yuliya22 [10]
4 years ago
6

A runner traveled 15 kilometers north then backtracked 11 kilometers south before stopping. His resultant displacement was

Physics
2 answers:
Vanyuwa [196]4 years ago
5 0

displacement is 4 km in north direction.


Explanation:

we are given

 A runner traveled 15 kilometers north first

then backtracked 11 kilometers south

we have to find displacement=d=?

assume that  east side represents +ve x- axis(horizontal)

and

north represent +ve y - axis (vertical)

we can take  x-axis (horizontal) as  i

and y-axis (vertical) as j.

Displacement = 15 j -11 j = 4 km north


Serhud [2]4 years ago
4 0

<u>Answer:</u>

 Resultant displacement is 4 km north.

<u>Explanation:</u>

    Let east represents positive x- axis and north represent positive y - axis. Horizontal component is i and vertical component is j.

   A runner traveled 15 kilometers north then backtracked 11 kilometers south before stopping,

   So initial displacement, 15 kilometers north = 15 j km

        Second displacement, 11 kilometers south = -11 j km

   Total displacement = 15 j -11 j = 4 j km

   Total displacement is 4 km north.

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1000 kgm²/s, 1000 J

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L=mvr+mvr\\\Rightarrow L=2mvr\\\Rightarrow L=2\times 100\times 2\times 2.5\\\Rightarrow L=1000\ kgm^2/s

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E_2=mv_f^2\\\Rightarrow E_2=100\times 10\\\Rightarrow E_2=1000\ J

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W=E_2-E\\\Rightarrow W=1000-400\\\Rightarrow W=600\ J

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