D) decreasing the temperature lowers the average kinetic energy of the reactants.
Based on the attached image:
- The name of the longitude line that passes through point A is the International Date Line
- The longitude 180° is experiencing solar noon because the rays of the sun are parallel to it.
- The longitude for 6 pm is 90° W, 12 midnight is 0°, and 6 am is 90° E
- Longitude 120° is B
- Solar time at Point B is 4 pm
- The location will correspond to any point on the same latitude as A
<h3>What are lines of longitude?</h3>
Lines of longitude are imaginary lines which run along the earth from the North pole. to the South pole.
Longitude lines divide the earth into semi-circles.
Longitude lines are known as meridians and each meridian measures one arc degree of longitude.
Considering the attached image:
- The name of the longitude line that passes through point A is the International Date Line
- The longitude 180° is experiencing solar noon because the rays of the sun are parallel to it.
- The longitude for 6 pm is 90° W, 12 midnight is 0°, and 6 am is 90° E
- Longitude 120° is B
- Solar time at Point B is 4 pm
- the location will correspond to any point on the same latitude as A
In conclusion, longitude lines are imaginary lines and run from North to South on the earth.
Learn more about lines of longitude at: brainly.com/question/1939015
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Answer:
0.572
Explanation:
First examine the force of friction at the slipping point where Ff = µsFN = µsmg.
the mass of the car is unknown,
The only force on the car that is not completely in the vertical direction is friction, so let us consider the sums of forces in the tangential and centerward directions.
First the tangential direction
∑Ft =Fft =mat
And then in the centerward direction ∑Fc =Ffc =mac =mv²t/r
Going back to our constant acceleration equations we see that v²t = v²ti +2at∆x = 2at πr/2
So going backwards and plugging in Ffc =m2atπr/ 2r =πmat
Ff = √(F2ft +F2fc)= matp √(1+π²)
µs = Ff /mg = at /g √(1+π²)=
1.70m/s/2 9.80 m/s² x√(1+π²)= 0.572
Let's call the constant acceleration a.
At a time t, its speed will thus be v(t)=a*t+v0 where v0 is its initial speed, here 10 m/s. Hence v(t)=a*t+10.
From there we can deduce the position P(t)=a*t^2/2+10t+p0 where p0 is the initial position, here 0.
Hence P(t)=a*t^2/2+10t
Let's call T the time at which it's at 50 m/s, we know that P(T)=225m and that v(T)=50 m/s hence a*T+10=50 thus a=40/T and P(T)=(40/2+10)T=30T
Hence T=225/30=7.5
It took 7.5 seconds
C.
Because it’s falling it has acceleration in the y direction. If you have acceleration, you usually also have velocity, and since kinetic energy is KE= Mv^2 you know you have it. It also has potential energy because it has some height to it, and PE= Mgh.
