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svet-max [94.6K]
2 years ago
7

Most ozone is found in a region of Earth’s

Physics
1 answer:
kaheart [24]2 years ago
7 0

Answer:

It’s stratosphere

Explanation:

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1. how can the school and community help you to stay healthy and be aware of your health status?
Molodets [167]

Answer:

1.school and community helps in growth and development of you social health as when u learn how to be compatible with the people around you, you will do better in life

2. by trying and solving

by not giving

by innovating

by being motivated

BY KNOWING THAT U CAN DO IT

7 0
2 years ago
A volcano erupts and launches a chunk of hot magma horizontally with a speed of 252 m/s. The magma travels a horizontal distance
ArbitrLikvidat [17]

Answer:

The value is v_y  =  -48.61 \ m/s

Explanation:

From the question we are told that

   The horizontal speed is  u_x  = 252 \  m/s

    The horizontal distance is  d = 1250 \ m

Generally the time taken by the hot magma in air before landing is mathematically represented as

       t = \frac{d}{u_x}

=>    t = \frac{ 1250 }{252}

=>    t = 4.96 \  s

Generally the initial vertical velocity of the magma when it was lunched is  

    u_y = 0 \ m/ s

Then the final velocity of the magma when it hits the ground is mathematically represented s

       - v_y  =  u_y + gt

Here the negative sign mean that the direction of the velocity is towards the negative y -axis

So  

        - v_y  =  48.61 \ m/s

=>     v_y  =  -48.61 \ m/s

7 0
2 years ago
45. What is the wovelength of a 30. Hertz periodic
Leviafan [203]

The wavelength is 2m.

Hence, Option c) 2m is the correct answer

Given that;

Frequency; f = 30Hz

Speed; v = 60m/s

Wavelength; \lambda =\ ?

using the expression for the relations between wavelength, frequency and speed of wave:

\lambda = \frac{v}{f}

Where \lambda is wavelength, f is frequency and v is speed.

We substitute our given values into the equation

\lambda = \frac{60m/s}{30Hz}\\\\\lambda = \frac{60m/s}{30s^{-1}}\\\\\lambda = 2m

The wavelength is 2m.

Hence, Option c) 2m is the correct answer.

To learn more about wavelength, click here: brainly.com/question/1347107

4 0
2 years ago
If an electron moves in a circle of radius 21 cm perpendicular to a B field of 0.4 T, what are the speed of the electron and the
kodGreya [7K]

Answer:

a)

v = 4.048 *10^6 m/s

b)  

Angular frequency =  1.92 * 10^7

Explanation:

As we know

v =  \frac{qBr}{m}

q is the charge on the electron = 3.2 * 10^{-19} C

B is the magnetic field in Tesla = 0.4 T

r is the radius of the circle = 0.21 m

mass of the electrons = 6.64 * 10^{-27} Kg

a)

Substituting the given values in above equation, we get -

v = \frac{3.2 * 10^{-19}*0.4*0.21}{6.64 * 10^{-27}} \\v = 4.048 *10^6m/s

b)  

Angular frequency =

\frac{4.048 * 10^6 }{0.21} \\1.92 * 10^7

8 0
2 years ago
The 3rd question i need answers​
jeka94

Answer:

\sf{B. Two  \: quantities \:  can \:  have \:  the  \: same \:  dimensions \:  but  \: different  \: unit. }

4 0
2 years ago
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