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2 years ago

Most ozone is found in a region of Earth’s

Physics

1 answer:

kaheart [24]2 years ago

7 0

Answer:

It’s stratosphere

Explanation:

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Do acids or bases turn litmus paper red?

Tom [10]

Base => Blue

aciD => reD

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2 years ago

To view an enlarged upright image of an object through a simple magnifier, where must the object be located?.

Andre45 [30]

Answer:within the focal length of the lens, provided the focal length is shorter than the near point distance.

Explanation:Hope it helps

6 0

2 years ago

Oxygen has an atomic number of 8. What can you conclude from this fact?

Alja [10]

Answer:

The answer to your question is below

Explanation:

If Oxygen has an atomic number of 8, we can conclude that:

- If neutral, it has 8 protons and 8 electrons

- It has 8 neutrons and its atomic mass is 16 (A = 8 + 8)

- It must be located in the group VI A

- Its valence number must be 6

- Its Oxidation number is -2

7 0

2 years ago

A solid sphere of mass 8.6 kg, made of metal whose density is 3,400 kg/, hangs by a cord. When the sphere is immersed in a liqui

creativ13 [48]

Answer:

A. $1900 kg/m^3$

Explanation:

We are given that

$m=8.6 kg$

Density, $\rho_s=3400 kg/m^3$

Tension,T=38 N

We have to find the density of liquid.

$T=mg-\rho_l Vg$

$g=9.8 m/s^2$

Volume,V= $\frac{m}{\rho_s}$

$38=8.6\times 9.8-\rho_l\times \frac{8.6}{3400}\times 9.8$

$\rho_l\times \frac{8.6}{3400}\times 9.8=8.6\times 9.8-38$

$\rho_l=\frac{(8.6\times 9.8-38)\times 3400}{8.6\times 9.8}$

$\rho_l=1867kg/m^3\approx 1900 kg/m^3$

Option A is true.

4 0

2 years ago

An object of mass 3.4 kg is moving in a straight line with kinetic energy 59.177 J. A force is applied in the direction of its m

rusak2 [61]

Answer:

Its momentum is multiplied by a factor of 1.25

Explanation:

First, we calculate the initial velocity of the object:

K = 0.5 * m * v₁²

59.177 J = 0.5 * 3.4 kg * v₁²

v₁ = 5.9 m/s

With that velocity we can calculate the initial momentum of the object:

p₁ = v₁ * m

p₁ = 20.06 kg·m/s

Then we calculate the velocity of the object once its kinetic energy has increased:

(59.177 J) * 1.57 = 0.5 * 3.4 kg * v₂²

v₂ = 7.4 m/s

And calculate the second momentum of the object:

p₂ = v₂ * m

p₂ = 25.16 kg·m/s

Finally we calculate the factor:

p₂/p₁ = 1.25

3 0

2 years ago