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Reika [66]
3 years ago
5

How do simple machines make work easier?

Physics
2 answers:
miss Akunina [59]3 years ago
8 0
It is A: They add energy to the work

Mrrafil [7]3 years ago
3 0

Answer:  D.  They increase the distance over which a force is applied.

Explanation:

Simple machines are basic mechanical devices which make our work easier like lever, pulley, wheel and axle, inclined plane, wedge and screw. The magnitude of the force or direction is altered using a simple machine. They increase the distance over which a force is applied. They use mechanical advantage to increase the magnitude of the force.

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A light ray hits a plane surface at 20 degrees. What is the angle between the incident and reflected rays.
Eduardwww [97]

Answer:

140°

Explanation:

The law of reflection states that the angle of redlection equals to the angle of incidence.

When light rays hit surface at 20°, they also leave the surface at the same angle

Since the whole surface has 180° then subtracting these two angles from total angle gives the the angle between the incident and reflected rays.

180°-20°-20°=140°

The angle of incidence and reflection are equal hence 140/2=70°

The question needed the angle between the incident and reflected rays which is already calculated as 140°

7 0
3 years ago
75 POINTS AND BRAINLY
kramer

Answer:

B=work=power/time

Explanation:

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3 years ago
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Laws of motion are important for the study of objects that are not in motion and objects in motion. Is it true or false?
e-lub [12.9K]
Gotta be true because physics
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3 years ago
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Please help with the chart.
eimsori [14]
Unicellular: An organism that consists of a single cell

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3 years ago
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What is the strength of the electric field 3.0 cm from a small glass bead that has been charged to + 8.0 nc ?
Debora [2.8K]
Thinking the small glass bead as a single point charge, the electric field generated by it is given by
E(r) = k_e  \frac{Q}{r^2}
where
k_e = 8.99 \cdot 10^9 N m^2 C^{-2} is the Coulomb's constant
Q=8.0 nC=8.0 \cdot 10^{-9} C is the charge of the bead
r=3.0 cm=0.03 m is the distance at which we calculate the field.

Using these data, we find:
E=(8.99 \cdot 10^9 N m^2 C^{-2} ) \frac{(8.0 \cdot 10^{-9} C}{0.03 m)^2}=8.0 \cdot 10^4 N/C
6 0
3 years ago
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