By chromatography it's the answer
Answer:
D. 12.4 m
Explanation:
Given that,
The initial velocity of the ball, u = 18 m/s
The angle at which the ball is projected, θ = 60°
The maximum height of the ball is given by the formula
h = u² sin²θ/2g m
Where,
g - acceleration due to gravity. (9.8 m/s)
Substituting the values in the above equation
h = 18² · sin²60 / 2 x 9.8
= 18² x 0.75 / 2 x 9.8
= 12.4 m
Hence, the maximum height of the ball attained, h = 12.4 m
Answer:
v_y = 14.55 m/s
Explanation:
given,
height at which gull is flying = 10.80 m
speed of the gull = 6 m/s
acceleration due to gravity = 9.8 m/s²
Relative to the seagull, the x-speed is 0,
because the seagull has the same x-speed.
Only the y-speed counts:
v_y = 14.55 m/s
hence, the speed at which the clam smash the rock is v_y = 14.55 m/s
The pressure needed : 800 kPa
<h3>Further explanation</h3>
Given
V₁ = 0.4 m³
P₁ = 100 kPa
T₁ = 20 + 273 = 293 K
V₂ = 0.05 m³
T₂ = T₁ = 293 K
Required
The final pressure(P₂)
Solution
Boyle's Law
At a fixed temperature, the gas volume is inversely proportional to the pressure applied

Input the value :
P₂=P₁V₁/V₂
P₂=100 x 0.4 / 0.05
P₂=800 kPa
Formula for velocity:
V(t) = Vi + at
Where V(t) is velocity at time t, Vi is initital velocity, and a is acceleration.
Solving for a:
V(8) = Vi + a(8)
V(8) = 0 (car has stopped)
0 = 24 + 8a
-24 = 8a
a = -3 m/s/s