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2 years ago

Factors that affect the light intensity received from a source

1 answer:

6 0

Light intensity and distance is interrelated. When the distance changes, the intensity of light changes. This relationship is called inverse-square relationship. The inverse-square relationship refers to the fact that when distance changes, light intensity also changes: inverse because when distance decreases, light density increases and when distance increases, the latter decreases; square refers to the fact that light intensity and distance is not a one-to-one relationship.

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A 36,287 kg truck has a momentum of 907,175 kg • . What is the truck’s velocity?

Snowcat [4.5K]

By definition,
Momentum = Mass * Velocity

Let v = the velocity of the truck, m/s
The mass of the truck is 36,287 kg.
The momentum is 907,175 (kg-m)/s.

Therefore
907,175 (kg-m)/s = (36287 kg)*(v m/s)
v = 907175/36287 = 25 m/s

Answer: 25 m/s

7 0

3 years ago

Read 2 more answers

A stone is projected from the ground with a velocity 14m/s one second later it clears a wall 2 m high. The angle of projection i

Eva8 [605]

Answer:

30 degrees

i can't put in my work on paper

6 0

3 years ago

Read 2 more answers

I’d really appreciate it if someone could help

Vanyuwa [196]

Answer:

0.25

Explanation:

Friction force is the normal force times the coefficient of friction.

F = Nμ

50 N = (200 N) μ

μ = 0.25

6 0

3 years ago

A 60 g golf ball is dropped from a level of 2 m high. It rebounds to 1.5 m. How much energy is lost? Group of answer choices 0.5

bogdanovich [222]

Answer: A 60 g golf ball is dropped from a level of 2 m high. It rebounds to 1.5 m. Energy loss will be 0.29J

Explanation: To find the correct answer, we have to know more about the Gravitational potential energy.

<h3>What is gravitational potential energy?</h3>

The energy possessed by a body by virtue of its position in gravitational field of earth is called gravitational potential energy.
The gravitational potential energy of a body at a height h with respect to the height h will be,

$U=mgh$

Expression for gravitational potential energy loss will be,

$E=U_i-U_f$

<h3>How to solve the problem?</h3>

The total energy before the ball dropped will be,

$U_i=mgh_i=60*10^-3kg*9.8m/s^2*2m=1.176 J$

The total energy after when the ball rebounds to 1.5m will be,

$U_f=mgh_f=60*10^-3kg*9.8m/s^2*1.5m=0.882J$

The total energy loss will be,

$E=1.176-0.882=0.294J$

Thus, we can conclude that, the energy loss will be,0.294J.

Learn more about the gravitational potential energy here:

brainly.com/question/28044692

#SPJ4

3 0

1 year ago

A shotputter throws the shot with an initial speed of 15.6 m/s at a 30.0 degree angle to the horizontal. Calculate the horizonta

vfiekz [6]

To calculate the horizontal distance traveled by the shot if it leaves the athlete's hand at a height of 2.20 above the ground we can get the root of the quad equation for time are t=-0.24 or t =1.84 taking the t = 1.84, so the equation will be:
x = 15.6cos(30) * 1.86, x = 24.79m

8 0

2 years ago