What you want to do is solve all of these so that it equals to 0 on one side. The ones that are a quadratic will have x^2
x^2 - 2x = 4x + 1
x^2 - 6x - 1 = 0
Yes this is a quadratic
x^3 - 6x^2 + 8 = 0
No this is not a quadratic because the highest power of x is to the power of 3
5x - 3 = 0
No it is not a quadratic because it does not have x^2
2x^2 + 12x = 0
Yes because there's x^2
5x - 1 = 3x + 8
2x - 9 = 0
No because no x^2
9x^2 + 6x - 3 = 0
Yes because there's x^2
The answer is 1/24 because Chloe collected 4 times.
Answer:
283 is the answer
Step-by-step explanation:
Answer:
sdf67566655 so x is 129
Step-by-step explanation:
ytr654564676
9514 1404 393
Answer:
(x, y) = (-3, -13) or (-8, -23)
Step-by-step explanation:
The values for y can be equated and the resulting quadratic solved by factoring.
2x -7 = x^2 +13x +17
0 = x^2 +11x +24 . . . . . . subtract 2x-7
0 = (x +8)(x +3) . . . . . . . .factor*
The values of x that make these factors zero are x=-8 and x=-3. The corresponding values of y are ...
y = 2(-8) -7 = -23
y = 2(-3) -7 = -13
The solutions are ...
(x, y) = (-8, -23) and (-3, -13)
_____
* The constants in the binomial factors are factors of 24 that total 11. You know that ...
24 = 1×24 = 2×12 = 3×8 = 4×6
The sums of these factors are 25, 14, 11, 10. The factors 3 and 8 are the constants in the binomial factors of the quadratic.
"24" is the constant in the quadratic. "11" is the coefficient of the x term.