Answer:
R = 1,746 Ω
Explanation:
The power dissipated in the circuit is
P = V I = V² / R
Let's find the current
R = V² / P
Let's calculate
R = 13²/81
R = 2,096 Ω
This is total resistance
R_total = R + r
R = R_total - r
R = 2,096 -0,350
R = 1,746 Ω
Answer:
0.050V
Explanation:
To solve this problem it is necessary to use the concepts related to the potential between two objects that have a magnetic field, this concept is represented in the equation.
Where,
v= tangencial velocity
B = Magnetic Field
We know for definition that,
Where,
L = length
Angular velocity
We can replace this values in our first equation then,
Integrating we have,
Replacing the values,
Therefore the potential difference between the center of the rod and the other rod is 0.050V
The acceleration at the bottom of the loop is 34m/
Explanation:
<u>Given: </u>
Mass=52kg
Force=1750N
To calculate:
The acceleration at the bottom of the loop
<u>Formula:
</u>
Force=Mass x Acceleration
1750=52 x Acceleration
1750/52=Acceleration
Therefore acceleration at the bottom of the loop is 34m/
Roller coasters are mainly based upon acceleration theory they have two types of acceleration one is at the top of the loop and the other is at the bottom of the loop.
Then the net forces and the values are given. In many problems the roller coaster concept is included and it gives another level of clarity to the problems including the net forces
Answer: Ok, first lest see out problem.
It says it's a Long cylindrical charge distribution, So you can ignore the border effects on the ends of the cylinder.
Also by the gauss law we know that E¨*2*pi*r*L = Q/ε0
where Q is the total charge inside our gaussian surface, that will be a cylinder of radius r and heaight L.
So Q= rho*volume= pi*r*r*L*rho
so replacing : E = (1/2)*r*rho/ε0
you may ask, ¿why dont use R on the solution?
since you are calculating the field inside the cylinder, and the charge density is uniform inside of it, you don't see the charge that is outside, and in your calculation actuali doesn't matter how much charge is outside your gaussian surface, so R does not have an effect on the calculation.
R would matter if in the problem they give you the total charge of the cylinder, so when you only have the charge of a smaller r radius cylinder, you will have a relation between r and R that describes how much charge density you are enclosing.
Convection. It is the transfer of heat by the circulation and movement of the molecules that come from liquid or gas.