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Marrrta [24]
3 years ago
6

A tennis player on serve tosses a ball straight up. While the ball is in free fall, does its acceleration a. increaseb. decrease

c. increase then decreased. decrease then increasee. remain constant
Physics
1 answer:
Anna11 [10]3 years ago
6 0

Answer: Remains constant

Explanation:

The acceleration of the body under the free fall always remains constant. A body falling freely after reaching its maximum height when launched is under the influence of gravitational force (g) and the value is positive for downward fall.

Note that the acceleration possessed by the body is acceleration due to gravity which is the same at any point during the fall i.e 9.81m/s².

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Consider the two moving boxcars in Example 5. Car 1 has a mass of m1 = 65000 kg and a velocity of v01 = +0.80 m/s. Car 2 has a m
Amiraneli [1.4K]

Answer:

1.034m/s

Explanation:

We define the two moments to develop the problem. The first before the collision will be determined by the center of velocity mass, while the second by the momentum preservation. Our values are given by,

m_1 = 65000kg\\v_1 = 0.8m/s\\m_2 = 92000kg\\v_2 = 1.2m/s

<em>Part A)</em> We apply the center of mass for velocity in this case, the equation is given by,

V_{cm} = \frac{m_1v_1+m_2v_2}{m_1+m_2}

Substituting,

V_{cm} = \frac{(65000*0.8)+(92000*1.2)}{92000+65000}

V_{cm} = 1.034m/s

Part B)

For the Part B we need to apply conserving momentum equation, this formula is given by,

m_1v_1+m_2v_2 = (m_1+m_2)v_f

Where here v_f is the velocity after the collision.

v_f = \frac{m_1v_1+m_2v_2}{m_1+m_2}

v_f = \frac{(65000*0.8)+(92000*1.2)}{92000+65000}

v_f = 1.034m/s

8 0
4 years ago
ANswer the question and give example: Can friction ever perform positive work?
Harman [31]
Yes. Think of block sitting on top of a bigger block. If the bottom block moves, it will drag the top block with it. Since the force of friction on the small block and its displacement are in the same direction, the "work" is positive. The static friction is a passive force, It is not a source of energy; it transmits the force placed on the bottom block. (And the "work" done by the friction on the bottom block is exactly the negative of the work done on the top block.) 
4 0
4 years ago
Read 2 more answers
A constant current is sent through a helical coil. the coil
marissa [1.9K]

Answer:

A. Tends to get shorter.

Explanation:

When a constant current is sent through a helical coil, then currents are different turns will be equal as well as in the same direction. As currents in same direction attract each other, hence coil tends to get shorter.

5 0
3 years ago
A person who weighs 685 N steps onto a spring scale in the bathroom, and the spring compresses by 0.88 cm. (a) What is the sprin
kotykmax [81]

To solve this problem it is necessary to use the concepts of Force of a spring through Hooke's law, therefore,

F = kx

Where,

k = Spring constant

x = Displacement

Initially our values are given,

F = 685N

x = 0.88 cm

PART A ) With this values we can calculate the spring constant rearranging the previous equation,

k = \frac{F}{x}

k = \frac{685}{0.88*10^-2}

k = 77840.9N/m

PART B) Since the constant is unique to the spring, we can now calculate the force through the new elongation (0.38cm), that is

F = kx

F = (77840.9)(0.0038)

F = 295.79N

Therefore the weight of another person is 265.79N.

6 0
3 years ago
Which object would have more potential energy, a bowling ball stored on a high shelf, or a base ball on the same shelf? Why? Whi
Anettt [7]

Answer:

A bowling ball stored on a high shelf has more potential energy

A base ball on the same shelf should rather fall on my head

Explanation:

Potential energy =mgh where m= mass, g= gravitational force and h is height

The bowling ball is bigger and heavier than the base ball

which means more mass . The remaining parameters are constant.

This means the bowling ball has more potential energy.

Since the base ball is lighter then it’s preferable to land on someone’s head due to the lesser force it will expert and lesser pain too.

7 0
3 years ago
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