Answer:
31.2 m/s
Explanation:
= Frequency of approach = 480 Hz
= Frequency of going away = 400 Hz
= Speed of sound in air = 343 m/s
= Speed of truck
Frequency of approach is given as
eq-1
Frequency of moving awayy is given as
eq-2
Dividing eq-1 by eq-2
= 31.2 m/s
The observer can conclude that the sound is moving away from them and that its speed is increasing.
Answer:
Acceleration = 9 × 10^5 m/s^2 ( deceleration )
Explanation:
From the first equation of motion:
V = u + at
15000 = 30000 + 60a
a = ( 15000-30000)/60
a = 9 × 10^5 m/s^2
<u>We are given:</u>
Mass of the Steelhead(m) = 9 kg
Velocity of the Steelhead(v) = 16 m/s
<u>Calculating the Kinetic Energy:</u>
KE = 1/2mv²
replacing the variables
KE = 1/2 * 9 * (16)²
KE = 1152 Joules
C, planets orbit around the sun because of gravity
