Ask question

Ask question

All categories

3 years ago

6

A particle falling at its terminal speed vterm is in dynamic equilibrium with no net force. Use Newton's second law for this par

ticle falling in the presence of a downward electric field of strength E, to find an expression for vterm.

1 answer:

Ilya [14]3 years ago

3 0

Es la A por que des dije ensslzvsnald. Xbsalbxhdjdjwsbdbd

You might be interested in

A small 25 kilogram canoe is floating downriver at a speed of 1 m/s. What is the canoe’s kinetic energy?

Helen [10]

Kinetic energy = 1/2mv^2

=1/2(25)(1^2)
= 12.5J

4 0

3 years ago

Starting from rest, a 68.0 kg woman jumps down to the floor from a height of 0.790 m, and immediately jumps back up into the air

Aleonysh [2.5K]

Answer:

a) I = 0 N s, b) v = -3.935 m / s, c) vf = 3.935 m / s, d) y = 0.790 m

Explanation:

a) Let's start by defining the upward direction (+ y) as positive. For this part of the exercise we must use the momentum relationship

I = ∫F dt

The force of the woman on the floor is given and by action and rection the floor exerts on the woman a force of equal magnitude, but opposite direction

I = ∫ (9200 t - 11500 t2) dt

I = 9200 t² / 2 - 11500 t³ / 3

We evaluate between the lower limit t = 0 and upper limit t = 0.800 s

I = 9200 (0.8² -0) - 11500 (0.8³ -0)

I = 5888 -5888

I = 0 N s

Directed from the floor to the woman

b) For this part we use kinematics

v² = v₀² - 2g y

v = √ (0 - 2 9.8 (-0.79))

v = 3.935 m / s

The speed direction is down

c) for this we use the relationship between momentum and the amount of movement

I = ΔP

I = m vf - m v₀

vf = (I + m v₀) / m

This is the impulse of women on the floor

vf = ( 0 + 68 (3.935)) / 68

vf = 3.935 m / s

d) let's use kinematics

v₂ = v₀² - 2gy

0 = v₀² - 2gy

y = v₀² / 2g

y = 3.935²/2 9.8

y = 0.790 m

8 0

3 years ago

water flows through a horizontal pipe with a cross-sectional area of 4m^2 at a speed of 5m/s with a pressure of 300,000pa at poi

LenKa [72]

The velocity at point B is 10 m/s with a pressure of 262500 Pa

<h3>Bernoulli equation</h3>

According to the continuity equation:

A₁V₁ = A₂V₂

Where A is the area and V is velocity, ρ = density of water = 1000 kg/m³

Hence:

4(5) = 2(V₂)

V₂ = 10 m/s

Using Bernoulli equation:

$P_1+\rho gh_1+\frac{1}{2}\rho V_1^2= P_2+\rho gh_2+\frac{1}{2}\rho V_2^2\\\\Hence:\\\\300000+\rho gh+(0.5)*1000*5^2=P_2+\rho gh+(0.5)*1000*10^2\\\\P_2=262500\ Pa\\$

The velocity at point B is 10 m/s with a pressure of 262500 Pa

Find out more on Bernoulli equation at: brainly.com/question/14082066

6 0

2 years ago

What is the period of a water wave with a frequency of 0.5Hz

stiv31 [10]

Answer:

a wave with a time period of 2 seconds has a frequency of 1 ÷ 2 = 0.5 Hz. A sound wave has a time period of 0.0001 seconds.

8 0

2 years ago

Which statement correctly describes how the endocrine system interacts with the circulatory system? A.)The endocrine system uses

blagie [28]

Answer:

C.)The endocrine system uses glands to produce hormones that travel with the blood through the blood vessels.

Explanation:

8 0

3 years ago