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mash [69]
3 years ago
8

A variable force of 6x−2 pounds moves an object along a straight line when it is x feet from the origin. Calculate the work done

in moving the object from x = 1 ft to x = 18 ft. (Round your answer to two decimal places.) ft-lb

Physics
1 answer:
Marianna [84]3 years ago
3 0

Answer:

931.00ft-lb

Explanation:

Pls see attached file

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Please help me Calculate the total energy stored in the capacitor​
Neko [114]

La fórmula: P = W/t  ó  W = P x t. donde:

P = potencia

W = trabajo

t = tiempo

Otra fórmula de potencia es: P= I x V

Proceso de carga de un capacitor - condensador

Una fórmula muy importante que también hay que tener en cuenta es: V = q/C que indica que el voltaje es proporcional a la carga que hay en un condensador.

De la fórmula de potencia P= I x V y considerando que la corriente es constante (corriente continua), entonces la potencia es proporcional al voltaje.  Si el voltaje aumenta en forma lineal, la potencia aumentará igual. Ver el siguiente diagrama.

Como la potencia varía en función del tiempo, no se puede aplicar la fórmula W = P x t, para calcular la energía transferida. Pero observando el gráfico, se ve que esta energía se puede determinar midiendo el área bajo la curva de la figura.

Energía Almacenada en un Condensador - Capacitor

 

El área bajo la curva es igual a la mitad de la potencia en el momento “t”, multiplicada por “t”.

Entonces: W = (P x t) / 2. Pero se sabe que P = V x I. Si se reemplaza esta última fórmula en la anterior se obtiene: W = (V x I x t) / 2, y como I x t = CV = Q, entonces para saber cuanta energía (W) hay en un condensador usamos una de las siguientes fórmulas:

W = (CV2/2) julios

W = (QV/2) julios

W  = (Q2/2C) julios

, donde:

W = Trabajo (Energía) en julios

C = Capacidad en faradios

V = voltaje en voltios en los extremos del condensador

Q = carga del condensador

3 0
3 years ago
Read 2 more answers
If a load of 5 kg covers a distance of 50m in 2 min, what is the power? (g=10m/s)​
eduard

Explanation:

the answer is above with its si unit

3 0
2 years ago
Question number 11 how did we found the answer ?
BaLLatris [955]

Answer:

Option A. 57.14 Ω

Explanation:

From the question given above, the following data were obtained:

Resistor 1 (R₁) = 100 Ω

Resistor 2 (R₂) = 400 Ω

Resistor 3 (R₃) = 200 Ω

Equivalent Resistor (Rₚ) =?

The equivalent resistor in the above circuit can be obtained as follow:

1/Rₚ = 1/R₁ + 1/R₂ + 1/R₃

1/Rₚ = 1/100 + 1/400 + 1/200

Find the least common multiple (lcm) of 100, 400 and 200. The result is 400. Divide 400 by 100, 200 and 400 respectively and multiply the result with the numerator as shown

1/Rₚ = (4 + 1 + 2)/400

1/Rₚ = 7/400

Invert

Rₚ = 400/7

Rₚ = 57.14 Ω

6 0
3 years ago
Match each chemical name with the correct chemical formula.
pochemuha
Is there any chemical names listed ?
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Plz help i need help on my homework
tatiyna
The resultant force is 4 N to the right.
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4 years ago
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