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podryga [215]
3 years ago
7

1.) True or False.

Physics
1 answer:
eimsori [14]3 years ago
6 0

Answer:

Explanation:

According to Newton's third law of motion, forces always act in equal but opposite pairs. Another way of saying this is for every action, there is an equal but opposite reaction. This means that when you push on a wall, the wall pushes back on you with a force equal in strength to the force you exerted. 1.True 2.falues 3.true 4. not really sure on this one

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The oscillating electric field in a plane electromagnetic wave is given by <img src="https://tex.z-dn.net/?f=%7B50%5Csin%20%28%5
Scorpion4ik [409]

Here, we are given with:

{:\implies \quad \longrightarrow \begin{cases}\sf E_{0}= 50\: V/m\\ \sf \nu = 2\times 10^{7}Hz\end{cases}}

(a) So now, we can thus obtain

{:\implies \quad \sf \omega =2\pi \nu}

{:\implies \quad \sf \omega =2\pi (2\times 10^{7})}

{:\implies \quad \boxed{\bf{\omega = 4\pi \times 10^{7}\: s^{-1}}}}

Now, finding \lambda

{:\implies \quad \sf \lambda =\dfrac{c}{\omega}=\dfrac{3\times 10^{8}}{4\pi \times 10^{7}}}

{:\implies \quad \boxed{\bf{\lambda \approx 2.39\:m}}}

Now, finding k

{:\implies \quad \sf k=\dfrac{2\pi}{\lambda}=\dfrac{200\pi}{239}}

{:\implies \quad \boxed{\bf{k\approx 2.63\:m^{-1}}}}

Thus, expression for the electric field is:

{:\implies \quad \boxed{\bf{E=50\sin \bigg(4\pi \times 10^{7}t-\dfrac{263x}{100}\bigg)}}}

(b) Now, here

{:\implies \quad \sf B_{0}=\dfrac{E_{0}}{c}=\dfrac{50}{3\times 10^{8}}}

{:\implies \quad \boxed{\bf{B_{0}\approx 16.67×10^{-7}\:T}}}

Thus, expression for the magnetic field:

{:\implies \quad \boxed{\bf{B_{y}=16.67\times 10^{-7}\sin \bigg(4\pi \times 10^{7}t-\dfrac{263x}{100}\bigg)\:T}}}

(c) The electromagnetic wave propagates along Z-axis

4 0
2 years ago
A space ship has four thrusters positioned on the top and bottom, and left and right as shown below. The thrusters can be operat
Ugo [173]

Answer:

The correct answer is - c.  Spaceship will have a velocity to the East and will be slowing down.

Explanation:

In this case, if turned on thruster #2 then it will exert force on the west side as thruster 2 is on the east side and it can be understood by Newton's third law that says each action has the same but opposite reaction.

As the spaceship engine applies force on the east side then according to the law the exhauster gas applies on towards west direction. It will try to decrease the velocity of the spaceship however, the direction of floating still be east side initally.

8 0
3 years ago
There are three naturally occurring isotopes
mote1985 [20]

Explanation:

^{41}\text{Hi}: 41.000\:\text{g/mol}×0.283 = 11.603\:\text{g/mol}

^{42}\text{Hi}: 42.000\:\text{g/mol}×0.429 = 18.018\:\text{g/mol}

^{44}\text{Hi}: 44.000\:\text{g/mol}×0.288 = 12.672\:\text{g/mol}

Adding all the weighted values on the right hand side, we get

\text{Hi}: 42.293\:\text{g/mol}

7 0
3 years ago
A projectile is fired over level ground with an initial velocity that has a vertical component of 20 m/s and a horizontal compon
Anettt [7]
First of all, let's write the equation of motions on both horizontal (x) and vertical (y) axis. It's a uniform motion on the x-axis, with constant speed v_x=30 m/s, and an accelerated motion on the y-axis, with initial speed v_y=20 m/s and acceleration g=9.81 m/s^2:
S_x(t)=v_xt
S_y(t)=v_y t- \frac{1}{2} gt^2
where the negative sign in front of g means the acceleration points towards negative direction of y-axis (downward).

To find the distance from the landing point, we should find first the time at which the projectile hits the ground. This can be found by requiring
S_y(t)=0
Therefore:
v_y t -  \frac{1}{2}gt^2=0
which has two solutions:
t=0 is the time of the beginning of the motion,
t= \frac{2 v_y}{g} = \frac{2\cdot 20 m/s}{9.81 m/s^2}=4.08 s is the time at which the projectile hits the ground.

Now, we can find the distance covered on the horizontal axis during this time, and this is the distance from launching to landing point:
S_x(4.08 s)=v_x t=(30 m/s)(4.08 s)=122.4 m
4 0
3 years ago
Please help me, I’m confused on where to start.
zimovet [89]

Answer:

D

Explanation:

6 0
3 years ago
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