I think the correct answer is C
0.25 m/s squared
hope this helps x
Answer:
Explanation:
The two charges are q and Q - q. Let the distance between them is r
Use the formula for coulomb's law for the force between the two charges

So, the force between the charges q and Q - q is given by

For maxima and minima, differentiate the force with respect to q.

For maxima and minima, the value of dF/dq = 0
So, we get
q = Q /2
Now 
the double derivate is negative, so the force is maxima when q = Q / 2 .
Answer:
The electric potential (voltage)
produced by a point charge
, at any point in space, is given by the following equation:
Where:
is the Coulomb's constant
is the distance
The result is a scalar quantity, is defined as the electric potential energy per unit of charge and determines the electric influence exerted by the charge on that point of space.
Answer:
<em>The officer would calculate the similar value of Edef.</em>
Explanation:
As Edef is the energy required to deform the body therefore the reference frame does not affect the calculation of energy. In this context the value of Edef will remain same irrespective of fact, whichever frame of reference is used.