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podryga [215]
2 years ago
7

1.) True or False.

Physics
1 answer:
eimsori [14]2 years ago
6 0

Answer:

Explanation:

According to Newton's third law of motion, forces always act in equal but opposite pairs. Another way of saying this is for every action, there is an equal but opposite reaction. This means that when you push on a wall, the wall pushes back on you with a force equal in strength to the force you exerted. 1.True 2.falues 3.true 4. not really sure on this one

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As the shuttle bus comes to a sudden stop to avoid hitting a dog, it accelerates uniformly at -4.1 m/s^2 as it slows from 9.0 m/
zhuklara [117]

Acceleration  =  (change in speed) / (time for the change)

      - 4.1 m/s²  =  (-9 m/s)  /  (time for the change)

Time for the change  =  (-9 m/s) / (-4.1 m/s²)  =   2.2 seconds
3 0
3 years ago
As the temperature rises the solubility of all gases in water will _________
pav-90 [236]

Answer:

Decreases.

Explanation:

The rise in temperature of gas increases the kinetic energy of its molecules and they rush out of water instead of dissolving similarly as air rushes out of boiling water in form of bubbles

5 0
3 years ago
Which of the following is an example of newton second law of motion?
zaharov [31]

Answer: Its answer C: A wheelbarrow is more difficult to move as More objects are placed inside.

Explanation: The greater the mass of the object the more force is needed to make it move.

Hope this helps!! :)

4 0
3 years ago
A thermally insulated vessel containing a gas whose molar mass is equal to M and the ratio of specific heats cP /cV = γ moves wi
Vika [28.1K]

Answer:

∆T = Mv^2Y/2Cp

Explanation:

Formula for Kinetic energy of the vessel = 1/2mv^2

Increase in internal energy Δu = nCVΔT

where n is the number of moles of the gas in vessel.

When the vessel is to stop suddenly, its kinetic energy will be used to increase the temperature of the gas

We say

1/2mv^2 = ∆u

1/2mv^2 = nCv∆T

Since n = m/M

1/2mv^2 = mCv∆T/M

Making ∆T subject of the formula we have

∆T = Mv^2/2Cv

Multiple the RHS by Cp/Cp

∆T = Mv^2/2Cv *Cp/Cp

Since Y = Cp/CV

∆T = Mv^2Y/2Cp k

Since CV = R/Y - 1

We could also have

∆T = Mv^2(Y - 1)/2R k

6 0
3 years ago
When you drink cold water, your body must expend metabolic energy in order to maintain normal body temperature (37° C) by warmi
Gelneren [198K]

Answer:

7.72 Liters

Explanation:

normal body temperature = T_body =37° C

temperature of ice water = T_ice =0°c

specfic heat of water = c_{water} =4186J/kg.°C

if the person drink 1 liter of cold water mass of water is = m = 1.0kg

heat lost by body is Qwater =mc_{water} ΔT

                                           = mc{water} ( T_ice - T_body)

                                             = 1.0×4186× (0 -37)

                                             = -154.882 ×10^3 J

here negative sign indicates the energy lost by body in metabolic process energy expended due to brisk - hour long walk is Q_{walk} = 286 kilocalories

            = 286×4186J

so number of liters of ice water have to drink is

n×Q_{water} =Q_{walk}                                                                        n= Q_{walk}/ Q_{water}

= 286×4186J/154.882×10^3 J

 = 7.72 Liters

7 0
3 years ago
Read 2 more answers
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