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worty [1.4K]
4 years ago
7

The percent errors of your experimental values of the specific heats may be quite large. Identify several sources of experimenta

l error.
Chemistry
1 answer:
valkas [14]4 years ago
6 0

Answer:

The various sources of such errors are given below.

Explanation:

  • Sources of uncertainty or error could include necessary splattering of water leading to reduced cold water density as well as elevated temperatures of equilibration.
  • The temperature might not have been reasonably stable when developers evaluated at every phase of the investigation or research.

So that the percentage of someone specific produces heat exploratory value systems inaccuracies can be somewhat massive.

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Suppose that NaCl is added to hexane (C6H14) instead of water. Which of the following intermolecular forces will exist in the sy
svet-max [94.6K]

Answer:

Ion-ion force between Na+ and Cl− ions

London dispersion force between two hexane molecules

Explanation:

"Ion-dipole force between Na+ ions and a hexane molecule " does not exist since hexane has only non-polar bonds and therefore no dipole.

"Ion-ion force between Na+ and Cl− ions " exists since both are ions.

"Dipole-dipole force between two hexane molecules " does not exist since hexane molecules do not have a dipole.

"Hydrogen bonding between Na+ ions and a hexane molecule " does not exist since the hydrogen in the hydrogen bond must be bonded directly to an electronegative atom, which hexane does not have since it is a hydrocarbon.

"London dispersion force between two hexane molecules" exist since hexane is a molecular compound.

5 0
3 years ago
Read 2 more answers
H2 + O2 ---&gt; H2O<br> Classifying reaction
Degger [83]

Answer:

hydrogen + oxygen = water

3 0
3 years ago
Read 2 more answers
Which of the following is the name of the process scientists use to gain
kobusy [5.1K]

Scientific method

Explanation:

The scientific method is the name of the process scientists use to gain knowledge about the physical world.

The scientific method is a systematic approach into the study of nature. It follows the following processes:

  • Detailed observation
  • Asking of question
  • Formulation of hypothesis
  • Experimentation
  • Analysis and interpretation
  • Conclusion

learn more:

Experiment brainly.com/question/1621519

#learnwithBrainly

8 0
4 years ago
The following data were obtained in a kinetics study of the hypothetical reaction A + B + C → products. [A]0 (M) [B]0 (M) [C]0 (
Vladimir [108]

Answer:

B. First order, Order with respect to C = 1

Explanation:

The given kinetic data is as follows:

A + B + C → Products

     [A]₀     [B]₀    [C]₀       Initial Rate (10⁻³ M/s)

1.   0.4      0.4     0.2       160

2.  0.2      0.4      0.4       80

3.   0.6     0.1       0.2       15

4.   0.2     0.1       0.2        5

5.   0.2     0.2      0.4       20

The rate of the above reaction is given as:

Rate = k[A]^{x}[B]^{y}[C]^{z}

where x, y and z are the order with respect to A, B and C respectively.

k = rate constant

[A], [B], [C] are the concentrations

In the method of initial rates, the given reaction is run multiple times. The order with respect to a particular reactant is deduced by keeping the concentrations of the remaining reactants constant and measuring the rates. The ratio of the rates from the two runs gives the order relative to that reactant.

Order w.r.t A : Use trials 3 and 4

\frac{Rate3}{Rate4}= [\frac{[A(3)]}{[A(4)]}]^{x}

\frac{15}{5}= [\frac{[0.6]}{[0.2]}]^{x}

3 = 3^{x} \\\\x =1

Order w.r.t B : Use trials 2 and 5

\frac{Rate2}{Rate5}= [\frac{[B(2)]}{[B(5)]}]^{y}

\frac{80}{20}= [\frac{[0.4]}{[0.2]}]^{y}

4 = 2^{y} \\\\y =2

Order w.r.t C : Use trials 1 and 2

\frac{Rate1}{Rate2}= [\frac{[A(1)]}{[A(2)]}]^{x}[\frac{[B(1)]}{[B(2)]}]^{y}[\frac{[C(1)]}{[C(2)]}]^{z}

we know that x = 1 and y = 2, substituting the appropriate values in the above equation gives:

\frac{160}{80}= [\frac{[0.4]}{[0.2]}]^{1}[\frac{[0.4]}{[0.4]}]^{2}[\frac{[0.2]}{[0.4]}]^{z}

1 = (0.5)^{z}

z = 1

Therefore, order w.r.t C = 1

8 0
4 years ago
Volume occupied 3.52x10^32 moluchles<br>of Mathane (CH4)<br>1) At STP​
Naddika [18.5K]

Answer:

volume = 13097674418.528dm³

Explanation:

n = (3.52)*10^32/(6.02)*10^23)

n = (584717607.97)

n = volume /molar volume

molar volume at stp = 22.4dm³

volume= 584717607.97 x 22.4

volume = 13097674418.528dm³

6 0
3 years ago
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