Answer is: 22,65 gramsof methanol <span>must be burned.
</span>Chemical reaction: CH₃OH + 3/2O₂ → CO₂ + 2H₂O. ΔH = -764 kJ.
Make proportion, if one mole of ethanol release 764 kJ of heat, than:
1 mol : 764 kJ = n(CH₃OH) : 541 kJ.
n(CH₃OH) = 0,708 mol.
m(CH₃OH) = n(CH₃OH) · M(CH₃OH).
m(CH₃OH) = 0,708 mol · 32 g/mol.
m(CH₃OH) = 22,65 g.
Answer:
60.9 Kelvin
Explanation: First, write out everything that you know. You are tring to find the temperature, so the temperature will be represented by x.
Pressure (P)= 4.5 atm
Volume (V)= 3L
Number of Moles (n)= ?
Gas Consant (R)= 0.0821, if the pressure is in atm, that means r is 0.0821
Temperature (T)= x
We don't have all the information we need to plug the values into the equation. We still need to know how many moles 55.0 grans of neon is.
Ne in Grams= 55
Atomic Mass of Ne= 20.1797
55/20.1797= 2.7
moles= 2.7
Now that we have all the information we need, plug everying into the equation. In case you don't know, the Ideal Gas Law Equation is PV= nRT.
(4.5)(3) = (2.7)(0.821)x
x= 60.9
Now you have your temperature! It is 60.9 in Kelvin.
Answer:
0.67 g
Explanation:
We know that 1 mole of an element is 6.02 x 10^(23) atoms
Now, arsenic has 5.49 × 10²¹ atoms
Thus;
Number of moles of arsenic = 5.49 × 10²¹ × 1/6.02 x 10^(23) = 9 × 10^(-3) moles
We are told that;
one mole of arsenic = 74.92 g.
Thus, 9 × 10^(-3) moles = 9 × 10^(-3) × 74.92/1 = 0.67428 g ≈ 0.67 g
Answer :
(1) The correct option is, 2-ethylpentane
(2) The correct option is, 2,3-dimethylpentane
(3) The correct option is, 2-methyl-2-butene
(4) The correct option is, 7-ethyl-4-dodyne
(5) The correct option is, pentanoic acid
Explanation :
The basic rules for the naming of organic compounds are :
- First select the longest possible carbon chain.
- The longest possible carbon chain should include the carbons of double or triple bonds.
- The naming of alkane is done by adding the suffix -ane, alkene by adding the suffix -ene, alkyne by adding the suffix -yne and carboxylic acid by adding the suffix -oic acid.
- The numbering is done in such a way that first carbon of double or triple bond gets the lowest number.
- The carbon atoms of the double or triple bond get the preference over the other substituents present in the parent chain.
- If two or more similar alkyl groups are present in a compound, the words di-, tri-, tetra- and so on are used to specify the number of times of the alkyl groups in the chain.