Refer to the diagram. Which answer correctly labels the water between the equator and the North Pole?

Gravity provides a centripetal force on the Moon, helping it stay in orbit around Earth.

Elodia [21]

Answer:

The statement is true.

Both gravity and centrifugal force act on the Moon which causes it get pulled towards Earth (gravity) and get "flung away" so it doesn't hit us (centrifugal force).

4 0

4 years ago

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he triceps muscle in the back of the upper arm extends the forearm. This muscle in a professional boxer exerts a force of 2.00 1

meriva

Answer:

Moment of inertia = 0.3862kg-m²

Explanation:

2.00x10³

2.80cm

145 rad

r = r⊥ x F

F is an applied force

r⊥ is the distance between the applied force and axis

Force exerted = 2.00x10³

r⊥ = 2.8cm = 0.028m

Alpha = 145rad/s²

r = 0.028m x 2.00x10³

r = 56.0N-m

To get the moment of inertia

56.0N-m² = (145rad/s²) x I

The I would be:

I = (56.0N-m²)/(145rad/s²)

I = 56/145

= 0.3862Kg-m²

This is the moment of inertia.

Thank you!

5 0

3 years ago

A person lying on an air mattress in the ocean rises and falls through one complete cycle every five seconds. The crests of the

LuckyWell [14K]

Answer:

a) the frequency of the wave is 0.2 Hz

b) the speed of the wave 4 m/s

Explanation:

Given that;

time period = to complete one cycle t = 5 sec

frequency f = 1/t

frequency f = 1 / 5sec

f = 0.2 Hz

Therefore the frequency of the wave is 0.2 Hz

b)

speed of wave V = λf

given that our wavelength is 20.0 m

we substitute

speed of wave V = 20.0 × 0.2

speed of wave V = 4 m/s

Therefore, the speed of the wave 4 m/s

6 0

3 years ago

Distance Between Two Cars A car leaves an intersection traveling west. Its position 4 sec later is 19 ft from the intersection.

faltersainse [42]

Answer:

The answer to the question is;

The rate at which the distance between the two cars is changing is equal to 14.4 ft/sec.

Explanation:

We note that the distance traveled by each car after 4 seconds is

Car A = 19 ft in the west direction.

Car B = 26 ft in the north direction

The distance between the two cars is given by the length of the hypotenuse side of a right angled triangle with the north being the y coordinate and the west being the x coordinate.

Therefore, let the distance between the two cars be s

we have

s² = x² + y²

= (19 ft)² + (26 ft)² = 1037 ft²

s = $\sqrt{1037 ft^2}$ = 32.202 ft.

The rate of change of the distance from their location 4 seconds after they commenced their journeys is given by;

Since s² = x² + y² we have

$\frac{ds^{2} }{dt} = \frac{dx^{2} }{dt} + \frac{dy^{2} }{dt}$

→ $2s\frac{ds }{dt} = 2x\frac{dx}{dt} + 2y\frac{dy }{dt}$ which gives

$s\frac{ds }{dt} = x\frac{dx}{dt} + y\frac{dy }{dt}$

We note that the speeds of the cars were given as

Car B moving north = 12 ft/sec, which is the y direction and

Car A moving west = 8 ft/sec which is the x direction.

Therefore

$\frac{dy }{dt}$ = 12 ft/sec and

$\frac{dx}{dt}$ = 8 ft/sec

$s\frac{ds }{dt} = x\frac{dx}{dt} + y\frac{dy }{dt}$ becomes

$32.202 ft.\frac{ds }{dt} = 19 ft \times 8 \frac{ft}{sec} + 26ft\times 12\frac{ft}{sec}$ = 464 ft²/sec

$\frac{ds }{dt} = \frac{464\frac{ft^{2} }{sec} }{32.202 ft.}$ = 14.409 ft/sec ≈ 14.4 ft/sec to one place of decimal.

3 0

3 years ago

Serdar is interested in psychopathology and wants to go to graduate school and get a doctoral degree in psychology. His choice

masha68 [24]

<span>Serdar is interested in psychopathology and wants to go to graduate school and get a doctoral degree in psychology. His choice would most likely lead him toward a career as a </span>Clinical psychologist; doctors which focuses on diagnosing and treating mental, emotional, and behavioral disorders.

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3 years ago

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