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Tresset [83]
3 years ago
14

Which statement is true about the electromagnetic spectrum? The visible spectrum includes radio waves, light, and gamma rays. Th

e colors you can see have the same wavelength. It has a range of visible and invisible forms of radiation. The waves travel at the speed of 2.998×105 meters/second.
Physics
1 answer:
frozen [14]3 years ago
7 0

Answer: It has a range of visible and invisible forms of radiation.

Explanation:

Electromagnetic wave is defined as the wave which is associated with both electrical and magnetic component associated with them. They can travel in vacuum as well and travel with the speed of light i.e 2.998\times 10^8ms^{-1}

The electromagnetic radiations consist of radio waves, microwaves, infrared ,Visible , ultraviolet, X rays and gamma rays arranged in order of increasing frequency and decreasing wavelengths.

Only visible light is visible to naked eyes.

The relationship between wavelength and frequency of the wave follows the equation:

\nu=\frac{c}{\lambda}

where,

\nu = frequency of the wave

c = speed of light  

\lambda = wavelength of the wave

From the above relation, it is visible that wavelength and frequency follow inverse relation. For increase in wavelength, the value of frequency decreases and vice-versa.

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Honey solidifies from the bottom whereas water from the top. Why?
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Answer:

it is due to anamolous expansion of water as water cools from 4dg.c to 0dg.c. it expand making ice lighter than water to float

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3 years ago
A wheel rotates about a fixed axis with a constant angular acceleration of 4.0 rad/s2. The diameter of the wheel is 40 cm. What
Ray Of Light [21]

Answer:

v = 0.42m/s

Explanation:

In order o calculate the linear speed of the point at the border of the wheel, you first take into account that the total acceleration of such a point is given by:

a_{total}^2=a_r^2+a_t^2       (1)

atotal: total acceleration = 1.2m/s^2

ar: radial acceleration of the wheel

at: tangential acceleration

The tangential acceleration is also given by:

a_t=r\alpha     (2)

r: radius of the wheel = (40cm/2 )= 20cm = 0.2m

α: angular acceleration = 4.0rad/s^2

You replace the expression (2) into the expression (1) and solve for the radial acceleration:

a_{total}^2=a_r^2+(r\alpha)^2\\\\a_r=\sqrt{(a_{total})^2-(r\alpha)^2}\\\\a_r=\sqrt{(1.2m/s^2)^2-((0.2m)(4.0rad/s^2))^2}=0.894\frac{m}{s^2}

Next, you use the following formula for the radial acceleration and solve for the linear speed:

a_r=\frac{v^2}{r}\\\\v=\sqrt{ra_r}=\sqrt{(0.2m)(0.894m/s^2)}=0.42\frac{m}{s}

The linear speed of the point at the border of the wheel is 0.42m/s

5 0
3 years ago
QUICKK I NEED HELP!!<br> How is a mineral different from an element rock
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Answer:here you goo

Explanation:

A mineral is a naturally occurring inorganic element or compound having an orderly internal structure and characteristic chemical composition, crystal form, and physical properties. ... A rock is an aggregate of one or more minerals, or a body of undifferentiated mineral matter.

7 0
3 years ago
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V=IR
where V is the potential difference across the conductor, I is the current and R the resistance. Rearranging the equation, we get
R= \frac{V}{I}= \frac{15 V}{0.96 A}=15.6 \Omega

Now we can use the following equation to calculate the length of the wire:
R= \frac{\rho L}{A} (1)
where
\rho is the resistivity of the material
L is the length of the conductor
A is its cross-sectional area
In this problem, we have a wire of copper, with resistivity \rho=1.68 \cdot 10^{-8} \Omega m. The radius of the wire is half the diameter:
r= \frac{d}{2}= \frac{0.44 mm}{2}=0.22 mm=0.22 \cdot 10^{-3} m
And the cross-sectional area is
A=\pi r^2=\pi (0.22 \cdot 10^{-3}m)^2=1.52 \cdot 10^{-7} m^2

So now we can rearrange eq.(1) to calculate the length of the wire:
L= \frac{RA}{\rho}= \frac{(15.6 \Omega)(1.52 \cdot 10^{-7} m^2)}{1.68 \cdot 10^{-8} \Omega m}=141.1 m
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4 years ago
A solenoid of length 0.250 m and radius 0.0250 m is comprised of 440 turns of wire. Determine the magnitude of the magnetic fiel
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Answer: 0.02654

Explanation:

in the attachment

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4 years ago
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