Question

If 56 grams of carbon monoxide burns in oxygen to produce 88 grams of carbon dioxide, the mass of oxygen involved in the reaction is_____ grams. 32 56 88 144

Answer 1

Answer : The mass of oxygen involved in the reaction is, 32 grams.

Explanation : Given,

Mass of carbon monoxide = 56 g

Mass of carbon dioxide = 88 g

Molar mass of carbon monoxide $(CO)$ = 28 g/mole

Molar mass of oxygen $(O_2)$ = 32 g/mole

First we have to calculate the moles of carbon monoxide.

$\text{Moles of CO}=\frac{\text{Mass of CO}}{\text{Molar mass of CO}}=\frac{56g}{28g/mole}=2moles$

Now we have to calculate the moles of oxygen gas.

The balanced chemical reaction will be,

$2CO+O_2\rightarrow 3CO_2$

From the balanced chemical reaction, we conclude that

2 moles of CO react with 1 mole of $O_2$

So, the moles of $O_2$ = 1 mole

Now we have to calculate the mass of oxygen.

$\text{Mass of }O_2=\text{Moles of }O_2\times \text{Molar mass of }O_2$

$\text{Mass of }O_2=1mole\times 32g/mole=32g$

Therefore, the mass of oxygen involved in the reaction is, 32 grams.