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Answer :
(a) The acceleration of the car is,
(b) The distance covered by the car is, 150 m
Explanation :
By the 1st equation of motion,
...........(1)
where,
v = final velocity = 5 m/s
u = initial velocity = 25 m/s
t = time = 10 s
a = acceleration of the car = ?
Now put all the given values in the above equation 1, we get:
The acceleration of the car is,
By the 2nd equation of motion,
...........(2)
where,
s = distance covered by the car = ?
u = initial velocity = 25 m/s
t = time = 10 s
a = acceleration of the car =
Now put all the given values in the above equation 2, we get:
By solving the term, we get:
The distance covered by the car is, 150 m
The work done by the friction force to stop the player is equal to his loss of kinetic energy:
The work done by the friction force is the magnitude of the force
times the distance covered by the player, d:
The loss in kinetic energy is simply equal to the initial kinetic energy of the player, since the final kinetic energy is zero (the player comes to rest):
Substituting into the first equation, we get:
from which we find d, the distance covered by the player:
The work done by the friction force is the magnitude of the force
The loss in kinetic energy is simply equal to the initial kinetic energy of the player, since the final kinetic energy is zero (the player comes to rest):
Substituting into the first equation, we get:
from which we find d, the distance covered by the player: