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Yuki888 [10]
3 years ago
15

PLZ HELP ASAP, thanks :)

Chemistry
1 answer:
Basile [38]3 years ago
8 0

Answer:

2. \displaystyle S\:waves\:are\:also\:called\:secondary\:waves.

1. \displaystyle Ritcher\:scale

Explanation:

2. <em>Seismic</em> <em>waves</em> vibrate from side to side and up and down. They go through solids only, travel slower than <em>Pressure</em> [or <em>Primary</em>] <em>waves</em>, which arrive second, and shake the ground violently.

1. A <em>Ritcher</em><em> </em><em>scale</em><em> </em>senses the magnitude of earthquakes.

I am joyous to assist you anytime.

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NaOH+HCl-&gt;............
Oxana [17]

Answer:

NaCl+H20

Explanation:

It is a neutralisation reaction in which NaOH is a base and HCl is an acid. On reaction it forms salt and water.

Please mark as brainliest

3 0
2 years ago
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Will bromine water and magnesium react
bazaltina [42]
No. Magnesium, and Bromine are a chemical compound when put together.
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3 years ago
Tarnish on copper is the compound CuO. A tarnished copper plate is placed in an aluminum pan of boiling water. When enough salt
oksian1 [2.3K]

Answer:

The standard cell potential is 2.00 V

Explanation:

<u>Step 1:</u> Data given

Cu is cathode because of higher EP

Al3++3e−→Al       E∘=−1.66 V     anode

Cu2++2e−→Cu    E∘=0.340 V    cathode

<u>Step 2:</u> Balance both equations

2*(Al → Al3+-3e−)       E∘=1.66 V    

3*(Cu2++2e−→Cu)    E∘=0.340 V

<u>Step 3:</u> The netto equation

2 Al + 3Cu2+ +6e- → 2Al3+ + 3Cu -6e-

2 Al + 3Cu2+  → 2Al3+ + 3Cu

<u>Step 4:</u> Calculate the standard cell potential

E∘cell = E∘cathode - E∘anode

E∘cell = E∘ Cu2+/Cu - E∘ Al3+/Al

E∘cell =0.340 V - (-1.66) = 2.00 V

The standard cell potential is 2.00 V

4 0
2 years ago
The volume of a pond being studied for the effects of acid rain is 35 kiloliters (kL). There are 1,000 liters (L) in 1 kL and 1
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Answer:

35,000,000,000 mL

Explanation:

You first multiply 35 times 1000.

35,000 L

Now you multiply 35,000 times 10^6

35,000,000,000 mL

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3 years ago
Question is <br> P2O5 a ionic or covalent bond, its covalent right?
melisa1 [442]
Yes it is ========== covalent bond
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