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vladimir1956 [14]
3 years ago
15

Suppose we have two rock samples, A and B. If rock A was subject to both physical and chemical weathering while rock B was subje

ct to chemical weathering only. Which rock would experience more chemical weathering? why?
Chemistry
1 answer:
hammer [34]3 years ago
4 0

Answer:

Rock A because after physical weather and chemical weathering it more likely for Rock A to experience more chemical weathering.

Explanation: Weathering: This is a geological term used to describe the various processes and Activities involved in the breaking down of rocks either through physical,mechanical,chemical etc actions into smaller particles.

ROCK A WILL HAVE MORE CHEMICAL WEATHERING BECAUSE THE PHYSICAL WEATHERING MUST HAVE BROKEN DOWN THE PARTICLES FOR EASY WATER AND OTHER SUBSTANCE NEEDED FOR EASIER CHEMICAL REACTION OR WEATHERING.

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attashe74 [19]

Answer:

100

Explanation:

3 0
3 years ago
Read 2 more answers
EXPLAIN How would you explain the difference between single displacement and
IrinaK [193]
  • The difference between single displacement reaction and double displacement reaction are:

Explanation:

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3 0
2 years ago
I have seven energy levels, but only 1 valence eletron?
Olenka [21]

Answer:

Francium (Fr)

Explanation:

Looking at the periodic table, Francium has 7 energy levels as it is in the 7th Period and is in the 1st Group (meaning it has one electron in the outermost shell) which suggests that it has one valence electron.

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3 0
2 years ago
Please help me ASAP
blondinia [14]

Answer:

weak acid

Explanation:

pH scale is from 0 to 14

pH =7 is for water which is neutral.  it is neither acidic or basic as the hydrogen ion concentration is equal to hydroxyl ion concentration.

Lesser the pH value than 7 greater the acidic nature. And greater the pH value  than 7 more the basic nature.

Given pH=3-7 So the indicated interval represents weakly acidic.

4 0
3 years ago
How many moles is 22.4 liters of oxygen gas at standard temperature and pressure represent
makkiz [27]

Answer:

So 1 mole

Explanation:

PV = nRT

P = Pressure atm

V = Volume L

n = Moles

R = 0.08206 L·atm·mol−1·K−1.

T = Temperature K

standard temperature = 273K

standard pressure = 1 atm

22.4 liters of oxygen

Ok so we have

V = 22.4

P = 1 atm

PV = nRT

n = PV/RT

n = 22.4/(0.08206 x 273)

n  = 22.4/22.40

n = 1 mole

7 0
3 years ago
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