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vladimir1956 [14]
3 years ago
15

Suppose we have two rock samples, A and B. If rock A was subject to both physical and chemical weathering while rock B was subje

ct to chemical weathering only. Which rock would experience more chemical weathering? why?
Chemistry
1 answer:
hammer [34]3 years ago
4 0

Answer:

Rock A because after physical weather and chemical weathering it more likely for Rock A to experience more chemical weathering.

Explanation: Weathering: This is a geological term used to describe the various processes and Activities involved in the breaking down of rocks either through physical,mechanical,chemical etc actions into smaller particles.

ROCK A WILL HAVE MORE CHEMICAL WEATHERING BECAUSE THE PHYSICAL WEATHERING MUST HAVE BROKEN DOWN THE PARTICLES FOR EASY WATER AND OTHER SUBSTANCE NEEDED FOR EASIER CHEMICAL REACTION OR WEATHERING.

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If you have 2 Moles of C3H6 and 10 Moles of O2, which reactant is limiting the following reaction: 2C3H6 + 9O2 → 6CO2 + 6H2O?
Hatshy [7]

Answer:

The limiting reactant is propene, C_3H_6.

Explanation:

2C_3H_6 + 9O_2 \rightarrow 6CO_2 + 6H_2O

Moles of nitrogen propene  = 2 mol

Moles of oxygen  = 10 mol

According to reaction, 2 moles of propene reacts with 9 moles of oxygen gas, then 2 moles of propene will react with:

=\frac{9}{2}\times 2mol=9\text{mol of oxygen gas}

According to the question, we have 10 moles of oxygen gas, which is more than 9 moles of oxygen gas. This indicates that propene is present in a limiting amount hence, it is a limiting reactant.

The limiting reactant is propene, hence the correct answer is the C_3H_6.

5 0
3 years ago
What volume of carbon dioxide is produced when 0.489 mol of calcium carbonate reacts completely according to the following react
Vilka [71]

Answer:

11.0L of carbon dioxide is produced

Explanation:

Balanced equation: CaCO_{3}(s)\rightarrow CaO(s)+CO_{2}(g)

According to balanced equation, 1 mol of CaCO_{3} produces 1 mol of CO_{2}

So, 0.489 mol of CaCO_{3} produces 0.489 mol of CO_{2}

Let's assume CO_{2} behaves ideally.

So, P_{CO_{2}}V_{CO_{2}}=n_{CO_{2}}RT

where P is pressure, V is volume , n is number of moles, R is gas constant and T is temperature in kelvin

Plug-in all the values in the above equation-

(1atm)\times V_{CO_{2}}=(0.489mol)\times (0.0821L.atm.mol^{-1}.K^{-1})\times (273K)

or, V_{CO_{2}}=11.0L

So, 11.0L of carbon dioxide is produced

4 0
3 years ago
I have asked this question before but I was not clear enough. I want to prepare a 37% w/w solution (in water)of sulfuric acid fr
Zarrin [17]
Actually you have now a roport of 4:96 water to acid . All you have to do is add water to bring the raport to 37 acid and 63 water.
You need to have 0.5L mixture so
you have to have 18.5acid and the rest water 31.5
so for 18.5 acid you need to add 192.7 ml 96% acid and the rest water
4 0
4 years ago
Form of energy used to decompose water<br><br> it is a 11 letter word<br> _ _ e _ _ e _ c _ t _
andrew-mc [135]

Answer:

Electrolysis

Explanation:

Electrolysis is a process by which electrical energy is used to produce a chemical change. Perhaps the most familiar example of electrolysis is the decomposition (breakdown) of water into hydrogen and oxygen by means of an electric current. The same process can be used to decompose compounds other than water.

7 0
3 years ago
Read 2 more answers
Bobota
navik [9.2K]

Answer:

chemical stability

Explanation:

g goodnight

4 0
3 years ago
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