Answer:
1.200g
Explanation:
At the top it's 0 and that scale goes by 10s
The middle scale is 1 and it goes by 1s
The bottom scale is .2 and it goes by .1s
1+.2= 1.2 the extra zeroes are just place holders
1.200g
Answer:
0.0177 L of nitrogen will be produced
Explanation:
The decomposition reaction of sodium azide will be:
As per the balanced equation two moles of sodium azide will give three moles of nitrogen gas
The molecular weight of sodium azide = 65 g/mol
The mass of sodium azide used = 100 g
The moles of sodium azide used =
so 1.54 moles of sodium azide will give = mol
the volume will be calculated using ideal gas equation
PV=nRT
Where
P = Pressure = 1.00 atm
V = ?
n = moles = 2.31 mol
R = 0.0821 L atm / mol K
T = 25 °C = 298.15 K
Volume =
Answer: CO2 and H2O
Explanation: I already took the test it's right