- The work done is -30 J
- The heat is 25 J
<h3>What is the heat and the work?</h3>
We know that the work done by a gas could be positive or negative same as the heat. If the work done is positive then work is done on the system.
The work done is obtained from;
W = PΔV
W = 1.0 x 105 Pa(0.0006 m³ - 0.0003 m³)
W = 30 J
Given that the gas absorbs heat from the surroundings and the gas is expanding.
- The work done is -30 J
- The heat is 25 J
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Answer:
73325J
Explanation:
Given parameters:
Mass of water = 0.5kg
Initial temperature = 30°C
Final temperature = 65°C
Specific heat capacity = 4190J/kg°C
Unknown:
Amount of energy absorbed = ?
Solution:
The amount of energy absorbed can be derived using the expression below;
H = m c Δt
H is the amount of energy
m is the mass
c is the specific heat
Δt is the change in temperature
H = 0.5 x 4190 x (65 - 30 )
H = 73325J
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Explanation:
Let the east direction to be i^ and north direction be j^.
Thus displacement of the man S=8i^+6j^
So, magnitude of displacement ∣S∣=62+82=100=10 m
To solve this problem we will apply the principle of conservation of energy and the definition of kinematic energy as half the product between mass and squared velocity. So,
Here,
m = Mass
V = Velocity
Replacing,
Therefore the final kinetic energy of the two car system is 72.6kJ
the answer should be:
When the buoyant force is equal to the force of gravity
