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mario62 [17]
3 years ago
5

Does covalency fail in explaining the formation of BeCl2 and PCl5? Explain

Chemistry
1 answer:
Stolb23 [73]3 years ago
8 0

Answer:

Yes , covalency fails to explain the formation of BeCl₂ and PCl₅.

Explanation:

covalent bonds are formed between two atoms  by sharing of outermost electrons in order to attain octet for attaining stability . To octet means to attain 8 electrons in their outermost orbit .

BeCl₂ :

Be has two electrons in its outermost orbit and each of Cl has 7 electrons .

Each of Cl shares one electron each with each of two electrons of Be . Cl atoms attain 8 electrons as octet . But Be attains only 4 electrons ( 2 of Be and 2 from Cl atoms ) . Hence octet of Be is not attained . So covalency fails in the formation of BeCl₂ .

PCl₅ :

P has 5 electrons in the outermost orbit . Each of these electrons shares with one  electron from  each of Cl atoms . Thus Cl attains octel state ( 8 electrons ) but P attains 10 electrons ( 5 + 5 ) , 5 of P and 5 from 5 Cl atoms .

Hence Octet of P is not attained . Hence covalency fails in the formation of PCl₅ .

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Answer:

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Explanation:

The standard reduction potentials are

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Au³⁺(aq ) + 3e⁻  ⟶  Au(s);     1.42

Hg²⁺(aq)  + 2e⁻  ⟶  Hg(l);     0.85

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Cu²⁺(aq)   + 2e⁻ ⟶  Cu(s);   0.34

Mg2+(aq) + 2e- ⟶  Mg(s);   -2.38

The more negative the standard reduction potential, the stronger the metal is as a reducing agent.

Mg is the only metal with a standard reduction potential lower than that of Cu, so

Only Mg will react spontaneously with Cu²⁺.

 

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3 years ago
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3 years ago
You have 5 cars and you double that amount.How much cars do you have.
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3 years ago
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