Answer:
Because the optimal range of buffering for a formic acid potassium formate buffer is 2.74 ≤ pH ≤ 4.74.
Explanation:
Every buffer solution has an optimal effective range due to pH = pKa ± 1. Outside this range, there is not enough acid molecules or conjugate base molecules to sustain the pH without variation. There is a certain amount of both molecules that has to be in the solution to maintain a pH controlled.
Being for the formic acid the pKa 3.74, the optimal effective range is between 2.74 and 4.74. Upper or lower these range a formic acid/potassium formate buffer does not work.
The pressure of the gas is increased<span> to 224 </span><span>kPa</span>
The side of each water molecule with the oxygen atom uncovered will be marginally negative.
The side of each water molecule with the hydrogen atoms uncovered will be marginally positive.
So the two Cl{-} particles will be pulled in to the biggest number of positive charges, which happen in the boxes on the upper right and lower left.
The two Na{+} particles will be pulled in to the biggest number of negative charges, which happen in the boxes on the upper left and lower right.
Answer:
Calcium carbonate is another example of a compound with both ionic and covalent bonds.
Explanation:
In chemistry, an ionic compound is a chemical compound composed of ions held together by electrostatic forces termed ionic bonding. The compound is neutral overall, but consists of positively charged ions called cations and negatively charged ions called anions.
Using the equation PV = nRT
Therefore; V = nRT / P
Need moles of glucose converted to moles of the product gas (CO2).
Molecular weight calculation:
C 6 X 12.01 = 72.06
H 12 X 1.01= 12.12
O 6 X 16.00 = 96.00
sum = 180.18
25.5 g of C6H12O6 ( 1 mol C6H12O6 / 180.18 g) ( 6 mol CO2 / 1 mol C6H12O6) =
0.84915 mol CO2 gas.
Convert temp: 37 °C + 273.15 = 310.15 K
V= ((0.84915 mol)× (0.0821 L atm / mol K) (310.15 K))/0.980 atm
V = 22.0635 L
= 22.06 L CO2
