Answer:
37.8 L OF CARBON MONOXIDE IS REQUIRED TO PRODUCE 18.9 L OF NITROGEN.
Explanation:
Equation for the reaction:
2 CO + 2 NO ------> N2 + 2 CO2
2 moles of carbon monoxide reacts with 2 moles of NO to form 1 mole of nitrogen
At standard temperature and pressure, 1 mole of a gas contains 22.4 dm3 volume.
So therefore, we can say:
2 * 22.4 L of CO produces 22.4 L of N2
44.8 L of CO produces 22.4 L of N2
Since, 18.9 L of Nitrogen is produced, the volume of CO needed is:
44.8 L of CO = 22.4 L of N
x L = 18.9 L
x L = 18.9 * 44.8 / 22.4
x L = 18.9 * 2
x = 37.8 L
The volume of Carbon monoxide required to produce 18.9 L of N2 is 37.8 L
<span>The wave nature of an electron is indicated by its motion and the diffraction and interference of electrons in a beam.</span>
C6H10O5 (6 Carbon, 10 Hydrogen and 5 Oxygen)
Acids or bases<span> with weak bonds easily dissociate into ions and are called "</span>strong<span>" acids or </span>bases<span>. Table 1: Summary List of </span>Characteristics<span> for </span>Strong<span> and Weak Acids and </span>Bases<span>. All </span>characteristics<span> of acids and </span>bases<span> are related to whether the predominate forms are molecules and ions. </span>Characteristic<span>.</span>
5702.4 feet per sec
might want to cross check though