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Nady [450]
3 years ago
7

Calculate the pH of a solution that is 0.210 M in nitrous acid (HNO2) and 0.290 M in potassium nitrite (KNO2). The acid dissocia

tion constant of nitrous acid is 4.50 × 10-4.
Chemistry
1 answer:
jeka943 years ago
6 0

Answer:

pH = 3.49

Explanation:

We have a buffer system formed by a weak acid (HNO₂) and its conjugate base (NO₂⁻ coming from KNO₂). We can calculate the pH  of a buffer ssytem using the Henderson-Hasselbach equation.

pH = pKa + log [base] / [acid]

pH = -log Ka + log [NO₂⁻] / [HNO₂]

pH = -log 4.50 × 10⁻⁴ + log 0.290 M / 0.210 M

pH = 3.49

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Compounds X and Y both have the formula C7H14. Both X and Y react with one molar equivalent of hydrogen in the presence of a pal
ArbitrLikvidat [17]

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See explanation and image attached

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4 0
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Liquids and solids are referred to as "condensed phases" because the attractive forces cause molecules to become stationary. lea
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leave little space between the molecules.

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7 0
2 years ago
Read 2 more answers
If 1,079.75 Joules of heat are added to 77.75 grams of water, by how many degrees Celsius would the water increase? Assume water
djyliett [7]

Answer:

If 1,079.75 Joules of heat are added to 77.75 grams of water, by 3.32 degrees Celsius the temperature of  water will increase

\Delta T=3.32 C^{0}

Explanation:

q = mC\Delta T

Here , q = heat added / removed from the substance

m  = mass of the substance taken

\Delta T = Change in temperature

C = specific heat capacity of the substance

In liquid state the value of C for water is :

4.18 J/gC^{0}

Given values :

q = 1079.75 J

m = 77.75 gram

Insert the value of C, m , q in the given equation

q = mC\Delta T

on transposing ,

\Delta T=\frac{q}{mC}

\Delta T=\frac{1079.75}{77.75\times 4.18}

\Delta T=3.32 C^{0}

3 0
3 years ago
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