Write the empirical formula of at least four binary ionic compounds that could be formed from the following ions:
1 answer:
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194.5 g of BCl₃ is present in 1 × 10²⁴ molecules of BCl₃.
Explanation:
In order to convert the given number of molecules of BCl₃ to grams, first we have to convert the molecules to moles.
It is known that 1 moles of any element has 6.022×10²³ molecules.
Then 1 molecule will have moles.
So
Thus, 1.66 moles are included in BCl₃.
Then in order to convert it from moles to grams, we have to multiply it with the molecular mass of the compound.
As it is known as 1 mole contains molecular mass of the compound.
As the molecular mass of BCl₃ will be
Mass of boron is 10.811 g and the mass of chlorine is 35.453 g.
Molar mass of BCl₃ = 10.811+(3×35.453)=117.17 g.
So, 194.5 g of BCl₃ is present in 1 × 10²⁴ molecules of BCl₃.
C: 0.012 mol.
<h3>Explanation</h3>Start with 0.0020 moles of iodate ions .
How many moles of iodine will be produced?
converts to
in the first reaction. The coefficient in front of
is three times the coefficient in front of
. In other words, each mole of
will produce three moles of
. 0.0020 moles of
will convert to 0.0060 moles of
.
How many moles of thiosulfate ions are required?
reacts with
in the second reaction. The coefficient in front of
is twice the coefficient in front of
. How many moles of
does each mole of
consume? Two. 0.0060 moles of
will be produced. As a result,
moles of
will be needed.