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professor190 [17]
3 years ago
12

Help Pls thnk you !!!!!!!!!!!!!!!!!!!!!!!!!

Chemistry
1 answer:
uysha [10]3 years ago
3 0
The answer is double displacement is the answer
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I need help writing a LAB REPORT about NATURAL SELECTION
LekaFEV [45]

Answer:

Translate from Ukrainian.

У цей приклад я візьму селекції пшениці. Коли ми будемо говорити про селекцію цього злака, то ми можемо отримати меньшу собівартість, та вартість вирощування. Збільшена урожайність, та менша потреба в гербіцидах, пестицидах, та інсектицидах це теж наслідок. Тому селекція це майбутнє!

5 0
3 years ago
Give the ΔH value for the combustion of butane as shown in the reaction 2C4H10(g)+13O2(g)→8CO2(g)+10H2O(g)+5315 kJ.
777dan777 [17]

Answer:

ΔH = - 5315 kJ.

Explanation:

The given chemical reaction is as follows -

2C₄H₁₀ (g) + 13 O₂ (g)  →  8 CO₂ (g) + 10 H₂O (g) + 5315 kJ

In the above equation , the amount of energy i.e. 5315 kJ is released , i.e. it is in the product side , hence , the reaction is an example of an exothermic reaction .

Hence ,  

The value of the change in enthalphy , i.e. , the enthalpy of product minus the enthalpy of the product .

Therefore ,  

The value of the change in enthalphy = - ve .

Hence ,  

ΔH = - 5315 kJ.

7 0
3 years ago
Read 2 more answers
A bar of gold is 5.0mm thick, 10.0cm long and 2.0cm wide. It has a mass of exactly 193.0g. What is the desity of gold?
Tanzania [10]
<h3>Answer:</h3>

19.3 g/cm³

<h3>Explanation:</h3>

Density of a substance refers to the mass of the substance per unit volume.

Therefore, Density = Mass ÷ Volume

In this case, we are given;

Mass of the gold bar = 193.0 g

Dimensions of the Gold bar = 5.00 mm by 10.0 cm by 2.0 cm

We are required to get the density of the gold bar

Step 1: Volume of the gold bar

Volume is given by, Length × width × height

Volume =  0.50 cm × 10.0 cm × 2.0 cm

             = 10 cm³

Step 2: Density of the gold bar

Density = Mass ÷ volume

Density of the gold bar = 193.0 g ÷ 10 cm³

                                      = 19.3 g/cm³

Thus, the density of the gold bar is 19.3 g/cm³

3 0
2 years ago
How many liters of water would you need to add to 4.36 moles of NaCl to create a 9.4 M solution?
marishachu [46]

Answer:

0.464 L

Explanation:

Molarity (M) = number moles (n) ÷ volume (V)

According to the information given in this question:

number of moles (n) = 4.36 moles

Molarity = 9.4M

Volume = ?

Using M = n/V

9.4 = 4.36/V

9.4V = 4.36

V = 4.36/9.4

V = 0.464 L

Hence, 0.464L of water are needed the volume of water.

3 0
3 years ago
Part D
qwelly [4]

Answer:

Explanation:

The  number  on the top  right  of  the  symbol shows  ATOMIC NUMBER , if it is written alone only one digit or number overall .

And if the  number is also in bottom left then bottom left number will be ATOMIC NUMBER and top right will be MASS NUMBER

Hope  this will help you *-*

7 0
3 years ago
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