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3 years ago

When is the net force on an object equal to zero?

2 answers:

4 0

There are all kinds of conditions that could bring that about.

1. The most common one is friction. An object is moving that it is not accelerating. That means the frictional force is equal to the force causing motion.

2. The downward gravitational force is being negated by a rope suspending an object. The upward pull by the rope cancels the downward pull of gravity.

3. The rules of the game prohibit motion. A ballplayer would be stupid to leave second base while the pitcher has the ball in his hand (a physics joke. Please ignore).

4. A normal force upwards by the earth's surface is balanced by the weight of an object laying on the ground.

5. Speaking of baseball, there is no acceleration in the horizontal direction, so the net force on the ball horizontally is 0.

6. An elastic band held and aimed horizontally. The force of the elastic to launch a spitball vs the hand holding the elastic back waiting for the best time to let the spitball go.

That should get you going.

Rufina [12.5K]3 years ago

3 0

When ALL the forces are equal, or in general when <span>forces in the opposite direction are equal

so we can have newton example:

10 newtons X -10 newtons

netforce = 0 newtons</span>

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What is the magnitude of the force a 25 charge exerts on a 3 mc charge 35cm away?

lara31 [8.8K]

The electrostatic force between two charges is given by
$F=k_e \frac{q_1 q_2}{r^2}$
where
ke is the Coulomb's constant
q1 and q2 are the two charges
r is the separation between the charges

In our problem,
$q_1 = 25 \mu C=25 \cdot 10^{-6} C$
$q_2 = 3 mC = 3 \cdot 10^{-3} C$
$r=35 cm=0.35 m$
Therefore the electrostatic force is
$F=(8.99 \cdot 10^9 Nm^2C^{-2}) \frac{(25 \cdot 10^{-6}C)(3 \cdot 10^{-3}C)}{(0.35 m)^2}= 5510 N$

4 0

4 years ago

UTMSUNG

likoan [24]

Answer:

i think answer id leech because when it move it leave the liner

4 0

3 years ago

A mass of 3.6 kg oscillate on a horizontal spring with a spring constant of 160 N/m.

Darya [45]

Answer:

48.7 J

Explanation:

For a mass-spring system, there is a continuous conversion of energy between elastic potential energy and kinetic energy.

In particular:

- The elastic potential energy is maximum when the system is at its maximum displacement

- The kinetic energy is maximum when the system passes through the equilibrium position

Therefore, the maximum kinetic energy of the system is given by:

$KE=\frac{1}{2}mv^2$

where

m is the mass

v is the speed at equilibrium position

In this problem:

m = 3.6 kg

v = 5.2 m/s

Therefore, the maximum kinetic energy is:

$KE=\frac{1}{2}(3.6)(5.2)^2=48.7 J$

6 0

3 years ago

The damage caused by electric shock depends on the current flowing through the body; 1 ma can be felt and 5 ma is painful. above

WARRIOR [948]

We can solve the problem by using Ohm's law.

The resistance of the person, with dry skin, is $R=60000 \Omega$ . In order to be felt, the current must be at least
$I=1 mA=0.001 A$

Ohm's law gives us the relationship between current and voltage:
$V=IR$
where
I is the current
R the resistance
V the voltage

Using the data of the problem, we find that the minimum voltage needed is
$V=IR=(0.001 A)(60000 \Omega)=60 V$

3 0

4 years ago

_________ is the point on which a lever resets

Sergio [31]

Answer:

the answer is fulcrum because

Explanation:

lever is a simple machine consisting of a bar that rotates around a fixed point. The fixed point of a lever is called the fulcrum. Like other machines, a lever makes work easier by changing the force applied to the machine or the distance over which the force is applied

6 0

2 years ago