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blsea [12.9K]
3 years ago
11

The displacement ‘s' of a point moving in a straight line is given by: s = 6t^2 + 5t – 5, ‘s' being in cm and ‘t' in s. The init

ial velocity of the particle is:
Physics
1 answer:
Ivan3 years ago
6 0

Answer:

the initial velocity of the particle is 5 cm/s

Explanation:

Given initial displacement as, s = 6t² + 5t - 5

s is measured in "cm"

t is measured in "seconds"

Velocity is the rate of change of displacement with time. Expressed as follows;

v = \frac{ds}{dt} = 12t + 5

for initial velocity, time (t) = 0

v = 12(0) + 5

v = 5 cm/s

Therefore, the initial velocity of the particle is 5 cm/s

You might be interested in
A discus thrower turns with angular acceleration of 50 rad/s2, moving the discus in a circle of radius 0.80m. Find the radial an
anyanavicka [17]

Answer:

The value of tangential acceleration \alpha_{t} =  40 \frac{m}{s^{2} }

The value of radial acceleration \alpha_{r} = 80 \frac{m}{s^{2} }

Explanation:

Angular acceleration = 50 \frac{rad}{s^{2} }

Radius of the disk = 0.8 m

Angular velocity = 10 \frac{rad}{s}

We know that tangential acceleration is given by the formula \alpha_{t} = r \alpha

Where r =  radius of the disk

\alpha = angular acceleration

⇒ \alpha_{t} = 0.8 × 50

⇒ \alpha_{t} = 40 \frac{m}{s^{2} }

This is the value of tangential acceleration.

Radial acceleration is given by

\alpha_{r} = \frac{V^{2} }{r}

Where V = velocity of the disk = r \omega

⇒ V = 0.8 × 10

⇒ V = 8 \frac{m}{s}

Radial acceleration

\alpha_{r} = \frac{8^{2} }{0.8}

\alpha_{r} = 80 \frac{m}{s^{2} }

This is the value of radial acceleration.

7 0
3 years ago
I need help on all of this
wel

dude is -2m/s, ...ettte is +2m/s

pos vel is when dudette, eg, is going in increasing x, in this case.

neg vel  is when dudette, eg, is going in decreasing x, in this case. ie she turns round and runs

zero vel is zero speed. dudette standing still

positive vel neg pos top dia

no

yes

yes

yes

yes

yes

all yes looks like ...




4 0
3 years ago
7. If 8 million kg of water flows over Niagara Falls each second, calculate the power available at the bottom of the falls.
Alexxx [7]

Answer:

The power will be "3.92×10⁹ Watts". A further explanation is given below.

Explanation:

The given values as per the question,

Rate,

= 8 million kg

Distance,

= 50 m

Gravity,

= 9.8 m/s²

As we know,

The power will be:

⇒ Power = Rate\times Distance\times  Gravity

On putting the values, we get

⇒             =  8\times 10^6\times 50\times 9.8

⇒             =3.92\times 10^9 \  Watts

7 0
3 years ago
What is the biggest barrier to the use of renewable energy in the United States?
storchak [24]
The biggest barrier to the use of renewable energy in the United States is the  Citizen opposition to negative environmental impact.
So, the answer is B.
7 0
3 years ago
What is the formula you use to determine the gravitational potential energy of a object
kozerog [31]

Gravitational potential energy, relative to some level =

       (mass of the object)
times
       (height above the reference level)
times
       (acceleration due to gravity) .
4 0
3 years ago
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