Question

The displacement ‘s' of a point moving in a straight line is given by: s = 6t^2 + 5t – 5, ‘s' being in cm and ‘t' in s. The initial velocity of the particle is:

Answer 1

Answer:

the initial velocity of the particle is 5 cm/s

Explanation:

Given initial displacement as, s = 6t² + 5t - 5

s is measured in "cm"

t is measured in "seconds"

Velocity is the rate of change of displacement with time. Expressed as follows;

$v = \frac{ds}{dt} = 12t + 5$

for initial velocity, time (t) = 0

v = 12(0) + 5

v = 5 cm/s

Therefore, the initial velocity of the particle is 5 cm/s