The displacement ‘s' of a point moving in a straight line is given by: s = 6t^2 + 5t – 5, ‘s' being in cm and ‘t' in s. The init
1 answer:
Answer:
the initial velocity of the particle is 5 cm/s
Explanation:
Given initial displacement as, s = 6t² + 5t - 5
s is measured in "cm"
t is measured in "seconds"
Velocity is the rate of change of displacement with time. Expressed as follows;
for initial velocity, time (t) = 0
v = 12(0) + 5
v = 5 cm/s
Therefore, the initial velocity of the particle is 5 cm/s
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Answer:
Velocity (magnitude) is 98.37 m/s
Explanation:
We use the vertical component of the initial velocity, which is:
Using kinematics expression of vertical velocity (in y direction) for an accelerated motion (constant acceleration, which is gravity):
Now we need to find as a function of
. We use the horizontal velocity, which is always the same as follow:
We know the angle at 3 seconds:
Substitute in
and then solve for
With this expression we go back to the kinematic equation and solve it for initial speed
Recall this gas law:
=
P₁ and P₂ are the initial and final pressures.
V₁ and V₂ are the initial and final volumes.
T₁ and T₂ are the initial and final temperatures.
Given values:
P₁ = 475kPa
V₁ = 4m³, V₂ = 6.5m³
T₁ = 290K, T₂ = 277K
Substitute the terms in the equation with the given values and solve for Pf: