2 years ago

1. In 1897, I made a beam of electrons in a vacuum tube. Who

Chemistry

1 answer:

FromTheMoon [43]2 years ago

3 0

1. J. J. Thomson
2. Electrons
3. Ernest Rutherford
4. Nucleus

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What is the product when magnesium reacts with nitrogen? Mg(s) + N2(g) → Mg2N3(s) Mg3N(s) Mg3N2(s) MgN3(s)

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2 years ago

How much mass defect is required to release 5.5 x 1020 J of energy?

Montano1993 [528]

Answer : The mass defect required to release energy is 6111.111 kg

Explanation :

To calculate the mass defect for given energy released, we use Einstein's equation:

$E=\Delta mc^2$

E = Energy released = $5.5\times 10^{20}J$

$\Delta m$ = mass change = ?

c = speed of light = $3\times 10^8m/s$

Now put all the given values in above equation, we get:

$5.5\times 10^{20}Kgm^2/s^2=\Delta m\times (3\times 10^8m/s)^2$

$\Delta m=6111.111kg$

Therefore, the mass defect required to release energy is 6111.111 kg

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